flask sqlalchemy OperationalError：无法打开数据库文件

Question

我有一个烧瓶休息API。有一个函数，每分钟重复一次并更新数据库（sqlite3）。它工作了一段时间，但一段时间后API无响应，不会响应请求。我认为这个功能使API无响应。我可以看到问题标题中提到的错误。我在这里做错了吗？任何帮助表示赞赏。

from flask import Flask
from flask_sqlalchemy import SQLAlchemy
import threading
app = Flask(__name__)
db = SQLAlchemy(app)
app.config['SQLALCHEMY_DATABASE_URI'] = 'sqlite:///db.sqlite'
app.config['SQLALCHEMY_COMMIT_ON_TEARDOWN'] = True
.
.
.
def UpdateStatus():
threading.Timer(60, UpdateStatus).start() 
messages = Message.query.filter((Message.status != 'Seen')).all()
for msg in messages:
    try:
        messageid= msg.messageid
        wamessageid= msg.wamessageid
        timestamp= datetime.now()
        result= driver.get_message_status(wamessageid)
        if result==1:
            status='Sent'
            api_response= 'OK: Message sent'
        elif result==2:
            status= 'Delivered'
            api_response= 'OK: Message Delivered'
        elif result==3:
            status= 'Seen'
            api_response= 'OK: Message Seen'
        message = Message.query.filter_by(messageid = messageid).first()
        if message.status!= status:
            message.status= status
            message.apiresponse= api_response
            if status== 'Delivered':
                message.timestamp_delivered= timestamp
            if status== 'Seen':
                if message.timestamp_delivered is None:
                    message.timestamp_delivered= timestamp
                message.timestamp_seen= timestamp
            db.session.commit()
    except:
        traceback.print_exc()
        continue