Question

我有以下SQL

SELECT C.CUOCODE, C.NAME, COUNT(*) TOTAL_PAYMENT, SUM(P.AMOUNT) TOTAL_AMOUNT
FROM TAX_PAYMENT P
INNER JOIN TAX_CHECKPOINT C ON C.CUOCODE = REGEXP_SUBSTR(P.INVOICEID, 'R....')
WHERE DELETED = 0 AND TO_CHAR(TXTIME,'YYYY-MM-DD') = '2018-04-24'
GROUP BY  C.CUOCODE, C.NAME
ORDER BY TOTAL_AMOUNT DESC;

如何转换为laravel eloquent，我将“付款”模式（表TAX_PAYMENT）与“paymentid”作为主键。

Answer 1

DB::table('TAX_PAYMENT as P')
    ->select([
        'C.CUOCODE',
        'C.NAME',
        DB::raw('COUNT(*) AS TOTAL_PAYMENT'),
        DB::raw('SUM(P.AMOUNT) AS TOTAL_AMOUNT'),
    ])->Join('TAX_CHECKPOINT C', 'C.CUOCODE', '=', DB::raw('REGEXP_SUBSTR(P.INVOICEID,'R....')'))
    ->where('DELETED', 0)
    ->where(DB::raw("TO_CHAR(TXTIME,'YYYY-MM-DD')"), '2018-04-24')
    ->groupBy('C.CUOCODE')
    ->groupBy('C.NAME')
    ->orderBy('TOTAL_AMOUNT', 'desc')
    ->toSql();

输出

SELECT
    `C`.`CUOCODE`,
    `C`.`NAME`,
    COUNT(*) AS TOTAL_PAYMENT,
    SUM(P.AMOUNT) AS TOTAL_AMOUNT
FROM
    `TAX_PAYMENT` AS `P`
INNER JOIN `TAX_CHECKPOINT C` ON `C`.`CUOCODE` = REGEXP_SUBSTR (P.INVOICEID,"R....")
WHERE
    `DELETED` = ?
AND TO_CHAR (TXTIME, 'YYYY-MM-DD') = ?
GROUP BY
    `C`.`CUOCODE`,
    `C`.`NAME`
ORDER BY
    `TOTAL_AMOUNT` DESC

Answer 2

快速而肮脏的方式是使用Eloquents选择原始像：

 $result = DB::select( DB::raw("SELECT C.CUOCODE, C.NAME, COUNT(*) 
TOTAL_PAYMENT, SUM(P.AMOUNT) TOTAL_AMOUNT FROM TAX_PAYMENT INNER JOIN 
TAX_CHECKPOINT C ON C.CUOCODE
= REGEXP_SUBSTR(P.INVOICEID, 'R....') WHERE DELETED = 0 AND 
TO_CHAR(TXTIME,'YYYY-MM-DD') = '2018-04-24' GROUP BY  C.CUOCODE,
C.NAME ORDER BY TOTAL_AMOUNT DESC"));

如何将此SQL转换为Laravel雄辩？

2 个答案: