Question

SpringBoot 2.0.1。我正在尝试设置一个通用的“Address”对象，该对象可以附加到各种“AddressableDomainObject”对象上。下面的代码成功构建了Hibernate会话，但是当我尝试检索Company对象时，映射问题：

MappingException: Foreign key (FKk0e4770oa17lasc49nfp6mfxm:addresses [owner_object_type,owner_object_id])) must have same number of columns as the referenced primary key (contacts [id])

我想要它做的是“从地址中选择owner_object_id =？和owner_object_type ='COMPANY'”来构建列表。在地址方面，当owner_object_type ='COMPANY'时，它应“从id = addresses.owner_object_id的公司中选择”

表定义

create table addresses(
   id bigint,
   owner_object_type varchar(40),
   owner_object_id bigint,
   address ...
)
create table companies(
   id bigint,
   legal_name varchar(80),
   name ...
)

通用接口：

public interface AddressableDomainObject {

    public String getObjectType();
    public long getId();
}

package-info.java

@AnyMetaDef(
        name = "AddressableDomainObjectMetaDef",
        metaType = "string",
        idType = "long",
        metaValues = {
                @MetaValue(value = "CONTACT", targetEntity = Contact.class),
                @MetaValue(value = "COMPANY", targetEntity = Company.class)                    
        }
)

Company.java

@Entity
@Table(name = "companies")
@SequenceGenerator(name = "seq_companies", initialValue = 1)
@DiscriminatorValue("COMPANY")
public class Company implements AddressableDomainObject {
    @Id
    @GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "seq_companies")
    long id;

    String name;
    String legalName;
    String companyType;
    Long parentCompanyId;


    @Override
    public final String getObjectType(){
        return "COMPANY";
    }

    @OneToMany(
        mappedBy = "ownerObject",
        cascade = CascadeType.REMOVE)
    List<Address> addresses;
}

Address.java

@Entity
@Table(name = "addresses")
@SequenceGenerator(name = "seq_addresses", initialValue = 1)
public class Address implements UsableDomainObject {
    @Id
    @GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "seq_addresses")
    private long id;

    private String usage;

    private String address;
    private String address2;
    private String city;
    private String state;
    private String postalCode;
    private String country;
    private String gpsCoordinates;
    private String notes;

    @Any(
            metaDef = "AddressableDomainObjectMetaDef",
            metaColumn = @Column(name="owner_object_type")
    )
    @JoinColumn(name = "owner_object_id")
    private AddressableDomainObject ownerObject;
}

Hibernate JPA与@OneToMany映射到@Any而没有连接表

0 个答案: