Question

我需要组合两个数组。关于组合数组的大多数建议我都可以使用concat。但我不想添加到数组的末尾，我需要将array1中的键/值对添加到array2中的每个对象。

我需要合并这个array1：

[
    "Basket Abandonment",
    "Downloads",
    "App Version"    
]

使用这个array2：

[
    {
        bottom: {
            comp : "",
            details, : "3.1.39 22nd Jul 2015",
            status : "",
            title : "Previous Version",
            value : "8.7%"
        },
        top: {
            details: "3.1.40 25th August 2015", 
            status: "", 
            comp: "", 
            title: "Latest Version", 
            value: "86%",
        }
    },
    {
        bottom: {
            value: "469", 
            title: "Total Reviews", 
            status: "neutral", 
            comp: "same", 
            details: "2 New This Week"
        },
        top:  {
            details: "Version 3.1.40", 
            status: "neutral", 
            comp: "same", 
            title: "Average Rating", 
            value: "4.0"
        }
    },  
    {
        bottom: {
            value: "469", 
            title: "Total Reviews", 
            status: "neutral", 
            comp: "same", 
            details: "2 New This Week"
        },
        top:  {
            details: "Version 3.1.40", 
            status: "neutral", 
            comp: "same", 
            title: "Average Rating", 
            value: "4.0"
        }
    }       
]

在一个新的组合数组中，我需要为每个对象添加一个title的键使用第一个数组中的值，以便生成的数组如下所示：

[
    {
        title: "Basket Abandonment",
        bottom: {
            comp : "",
            details, : "3.1.39 22nd Jul 2015",
            status : "",
            title : "Previous Version",
            value : "8.7%"
        },
        top: {
            details: "3.1.40 25th August 2015", 
            status: "", 
            comp: "", 
            title: "Latest Version", 
            value: "86%",
        }
    },
    {
        title: "Downloads",
        bottom: {
            value: "469", 
            title: "Total Reviews", 
            status: "neutral", 
            comp: "same", 
            details: "2 New This Week"
        },
        top:  {
            details: "Version 3.1.40", 
            status: "neutral", 
            comp: "same", 
            title: "Average Rating", 
            value: "4.0"
        }
    },  
    {
        title: "App Version",
        bottom: {
            value: "469", 
            title: "Total Reviews", 
            status: "neutral", 
            comp: "same", 
            details: "2 New This Week"
        },
        top:  {
            details: "Version 3.1.40", 
            status: "neutral", 
            comp: "same", 
            title: "Average Rating", 
            value: "4.0"
        }
    }       
]

Answer 1

您可以在第二个数组中插入一个简单的for-loop，插入从第一个中获取的新title属性。但是，如果你想要一个在不修改源代码的情况下为你提供新数组的函数，那么一个解决方案就是在第二个数组中创建一个新数组mapping，并在第一个数组中包含字符串，如下所示：

let mixed = objects.map((obj, index) => (obj.title = titles[index], obj));

这里有一个使用数组函数的示例：

＆＃13;

let titles = [
  "Basket Abandonment",
  "Downloads",
  "App Version"
];

let objects = [
  {
    bottom: {
      comp: "",
      details : "3.1.39 22nd Jul 2015",
      status: "",
      title: "Previous Version",
      value: "8.7%"
    },
    top: {
      details: "3.1.40 25th August 2015",
      status: "",
      comp: "",
      title: "Latest Version",
      value: "86%",
    }
  },
  {
    bottom: {
      value: "469",
      title: "Total Reviews",
      status: "neutral",
      comp: "same",
      details: "2 New This Week"
    },
    top: {
      details: "Version 3.1.40",
      status: "neutral",
      comp: "same",
      title: "Average Rating",
      value: "4.0"
    }
  },
  {
    bottom: {
      value: "469",
      title: "Total Reviews",
      status: "neutral",
      comp: "same",
      details: "2 New This Week"
    },
    top: {
      details: "Version 3.1.40",
      status: "neutral",
      comp: "same",
      title: "Average Rating",
      value: "4.0"
    }
  }
];

const mix = (o, t) => o.map((m, i) => (m.title = t[i], m));

let mixed = mix(objects, titles);

console.log(mixed);

＆＃13;

合并没有concat的Javascript数组

1 个答案: