Question

 FILM_ID    TITLE       
---------- ---------- 
    1       Frozen,Frozen         
    2       Frozen,High,Low,High 


 FILM_ID    TITLE       
---------- ---------- 
    1       Frozen
    2       Frozen,High,Low

如果值为Frozen,Frozen我需要查询才能获得冻结以及第二个值我应该Frozen,High,Low

Answer 1

试试这个解决方案：

SELECT film_id, LISTAGG(title,',') WITHIN GROUP (Order BY title) TITLE
FROM 
(select distinct film_id, 
        regexp_substr(Title,'[^,]+', 1, level) as title
 from Table1
 connect by regexp_substr(Title, '[^,]+', 1, level) is not null
) t
GROUP BY film_id

<强>输出：

FILM_ID |  TITLE
--------------------------
 1      |  Frozen
 2      |  Frozen,High,Low

链接演示：

http://sqlfiddle.com/#!4/12377c/14

Answer 2

这是一个选项：

TEST是你的表
INTER以逗号分隔值创建行; DISTINCT在这里只返回不同的值（就像你想要的那样）
最终查询将它们聚合回来

SQL> with test (film_id, title) as
  2    (select 1, 'Frozen,Frozen'        from dual union
  3     select 2, 'Frozen,High,Low,High' from dual
  4    ),
  5  inter as
  6    (select distinct film_id, regexp_substr(title, '[^,]+', 1, column_value) title
  7     from test,
  8          table(cast(multiset(select level from dual
  9                              connect by level <= regexp_count(title, ',') + 1
 10                             ) as sys.odcinumberlist))
 11    )
 12  select film_id, listagg(title, ',') within group (order by title) title
 13  from inter
 14  group by film_id;

   FILM_ID TITLE
---------- ------------------------------
         1 Frozen
         2 Frozen,High,Low

我需要一个oracle查询来删除值中的重复项

2 个答案: