Question

在通过所有要求后，会发送已注册帐户的用户名和密码。必须包含1个小写，1个大写，1个数字和1个特殊字符，但由于某种原因，getParams（）方法不起作用..它表示void结果，但这是在volley中给出的确切代码。有什么问题？

package com.example.eid.authenticator;

import android.content.Intent;
import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.TextView;
import android.widget.Toast;
import java.util.HashMap;
import java.util.Map;
import com.android.volley.Response;
import com.android.volley.Request;
import com.android.volley.RequestQueue;
import com.android.volley.toolbox.JsonObjectRequest;
import com.android.volley.toolbox.StringRequest;
import com.android.volley.toolbox.Volley;
import com.android.volley.VolleyError;
import java.lang.Object;


public class RegisterActivity extends AppCompatActivity {

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_register);

        final TextView mTextView = (TextView) findViewById(R.id.text);
        // Request a string response from the provided URL.




        Button registerButton = findViewById(R.id.registerButton);


        registerButton.setOnClickListener(new View.OnClickListener() {

            @Override
            public void onClick(View v) {
                EditText username = (EditText)findViewById(R.id.usernameField);
                EditText password = (EditText)findViewById(R.id.passwordField);
                final String sUsername = username.getText().toString();
                final String sPassword = password.getText().toString();
                final RequestQueue queue = Volley.newRequestQueue(RegisterActivity.this);
                final String url = "10.0.2.2";
                if(sUsername.matches("")){
                    Toast.makeText(getApplicationContext(),"Please enter a username",Toast.LENGTH_SHORT).show();
                }else if(sPassword.matches("")){
                    Toast.makeText(getApplicationContext(),"Please enter a password",Toast.LENGTH_SHORT).show();

                }else if(sPassword.matches("^([^0-9]*|[^A-Z]*|[^a-z]*|[a-zA-Z0-9]*)$")){
                    Toast.makeText(getApplicationContext(),"Password must contain letters and numbers and uppercase",Toast.LENGTH_SHORT).show();


                }
            else if(sPassword.length() < 6){
                    Toast.makeText(getApplicationContext(),"Password must be greater than 6 characters",Toast.LENGTH_SHORT).show();


                }

                // TODO Auto-generated method stub
                else {

                    final StringRequest stringRequest = new StringRequest(Request.Method.GET, url,
                            new Response.Listener<String>() {
                                @Override
                                public void onResponse(String response) {
                                    // Display the first 500 characters of the response string.
                                    mTextView.setText("Response is: "+ response.substring(0,500));
                                }
                            }, new Response.ErrorListener() {
                        @Override
                        public void onErrorResponse(VolleyError error) {
                            mTextView.setText("That didn't work!");
                        }
                    })

                    @Override
                    protected Map<String,String> getParams(){
                        Map<String,String> params = new HashMap<String, String>();
                        params.put("user",sUsername);
                        params.put("pass",sPassword);


                        return params;
                    }




                    Intent i = new Intent(RegisterActivity.this, waitingPage.class);
                    startActivity(i);
                }
            }
        });
    }
}

这是错误的屏幕截图，它是我认为的语法，但我完全没有看到它。它看起来很好。

错误图片

Answer 1

GET 方法永远不会调用getParams()，如果您需要在 GET 中传递参数，则需要将其作为url params传递，getParams()会在 POST 请求中调用，请参阅下面的

将此转换为发布请求

 final StringRequest stringRequest = new StringRequest(Request.Method.POST, url,
                    new Response.Listener<String>() {

Answer 2

首先，您使用的是GET

Request.Method.GET

应该是POST喜欢

Request.Method.POST

您需要将getParams()方法保留在{ };内，如：

@Override
        public void onErrorResponse (VolleyError error){
            mTextView.setText("That didn't work!");
        }
    }) {

    @Override
    protected Map<String, String> getParams() {
        Map<String, String> params = new HashMap<String, String>();
        params.put("user", sUsername);
        params.put("pass", sPassword);


        return params;
    }
};

Answer 3

试试这个

您在getParams（）之前{之后忘记了})并且忘记了。{1}} getParams（）;

final StringRequest stringRequest = new StringRequest(Request.Method.POST, url,
                        new Response.Listener<String>() {
                            @Override
                            public void onResponse(String response) {
                                // Display the first 500 characters of the response string.
                                mTextView.setText("Response is: "+ response.substring(0,500));
                            }
                        }, new Response.ErrorListener() {
                    @Override
                    public void onErrorResponse(VolleyError error) {
                        mTextView.setText("That didn't work!");
                    }
                }) {

            @Override
            protected Map<String, String> getParams() {
                Map<String, String> params = new HashMap<String, String>();
                params.put("name", "Androidhive");
                params.put("email", "abc@androidhive.info");
                params.put("password", "password123");

                return params;
            }

        };

网址应为http://10.0.2.2/folder_name/login.php

Answer 4

将其更改为：

final StringRequest stringRequest = new StringRequest(Request.Method.POST, url,
                        new Response.Listener<String>() {

并将您的网址更改为：http://10.0.2.2/login.com

Answer 5

试试这个：

private void getRideStatus() {

    StringRequest req = new StringRequest(Request.Method.POST, Global.BASE_URL + Global.GET_RIDE_STATUS, new Response.Listener<String>() {

        @Override
        public void onResponse(String response) {
            Log.e("AA", response);

            try {
                JSONObject obj = new JSONObject(response);

                if (obj.getString("code").equals("1")) {
                    alertDialog(API.rMessage(obj));
                    loader.dismiss();
                    waitTimer.cancel();
                }
                else if (obj.getString("code").equals("2")) {

                    loader.show();


 //                        dialog.setMessage(obj.getString("message"));
//                        alertDialog(API.rMessage(obj));
//                        loader.dismiss();
                } else if (obj.getString("code").equals("3")) {
                    loader.dismiss();
                    alertDialog(API.rMessage(obj));
 //                        setAlert("Normal");
                    waitTimer.cancel();
                } else if (obj.getString("code").equals("4")) {

                    loader.dismiss();
                    waitTimer.cancel();
                    setAlert("Normal");
                }

            } catch (Exception e) {

                e.printStackTrace();
            }

        }

    }, new Response.ErrorListener() {
        @Override
        public void onErrorResponse(VolleyError error) {
        }
    }) {
        @Override
        protected Map<String, String> getParams() {
            //Pass the parameters to according to the API.
            Map<String, String> params = new HashMap<String, String>();
            Gson gson = new Gson();
            String json = Utils.getUserPreferences(HomeActivity.this, Global.RESPONSE_COUPON);
            CustomerCoupon obj = gson.fromJson(json, CustomerCoupon.class);
            params.put("user_token", Utils.getUser(HomeActivity.this).getUser_token());
            params.put("order_id", "");
            params.put("customer_latitude", String.valueOf(sourceLL.latitude));
            params.put("customer_longitude", "" + sourceLL.longitude);
            params.put("continue","");

            Log.e("AA", params.toString());
            return params;
        }
    };
    AppController.getInstance().addToRequestQueue(req);
}

发送用户名和密码到localhost无法正常工作？

5 个答案: