userRate :: Film -> Float
userRate (_,_,_,[],[]) = 0
userRate (_,_,_,likes,dislikes) = fromIntegral(length likes)/fromIntegral(length likes + length dislikes)* 100
---圆形用户评分的功能
websiteRating :: Film -> Int
websiteRating film = round(userRate (film))
- 函数使用列表推导来过滤网站评级为75及以上的电影
rating:: [Film] -> [Film]
rating films = [ film | film <-films , websiteRating film >=75]
我创建了一个功能,它给了我一个电影列表,只有那些显示网站评分高于75的电影,但我想在电影旁边添加网站评级
例如,这是显示的内容
Title: Silence
Director: Martin Scorsese
Year:2016
Website Rating : 76
Title: The Terminal
Director: Steven Spielberg
Year:2004
Website Rating : 76%
我想在列表中显示网站评级,我该怎么做? 感谢
答案 0 :(得分:0)
也许你正在寻找这样的东西,整个结果是一组由电影和评级组成的对。
//*********** IMPORTS *****************
var gulp = require('gulp'),
browserSync = require('browser-sync');
var postcss = require('gulp-postcss');
var less = require('gulp-less');
var watch = require('gulp-watch');
var livereload = require('gulp-livereload');
var autoprefixer = require('gulp-autoprefixer');
var concat = require('gulp-concat-css');
var cssmin = require('gulp-cssmin');
/* BROWSERSYNC */
gulp.task('browserSync', function () {
var files = ['orient-spa/**'];
browserSync.init(files, {
server: {
baseDir: 'orient-spa/',
index: 'index.html'
},
logPrefix: 'OS01',
browser: ['chrome']
});
});
gulp.task('css', function () {
var processors = [
autoprefixer
];
return gulp.src('./orient-spa/skins/less/index-files.less')
.pipe(less())
.pipe(postcss(processors))
.pipe(gulp.dest('./orient-spa/skins/css/'))
.pipe(livereload());
});
gulp.task('watch', function() {
livereload.listen();
gulp.watch('./orient-spa/skins/less/*.less', ['css']);
gulp.watch('./orient-spa/skins/css/*.css', ['concatMinify']);
});
gulp.task('concatMinify', function () {
return gulp.src('./orient-spa/skins/css/*.css')
.pipe(concat("index.css"))
.pipe(cssmin())
.pipe(gulp.dest('./orient-spa/skins/css/compiled'))
.pipe(livereload());
});
gulp.task('default', ['browserSync', 'watch', 'css', 'concatMinify']);