我在bash脚本中使用getopts
来传递2个参数。
我正在尝试在-c <component>
的输入上强制执行字符串匹配(使用if语句)以输入以下选项:
注意:它必须匹配这5个选项的确切字符串:
customer_builder
customer_service
historic_customer_builder
stream_builder
data_distributor
正在进行的代码:
# Usage for getopts
usage () {
echo -e "Usage:$0 -r region -c <component>"
echo -e "Available components:"
echo -e "customer_builder|customer_service|historic_customer_builder|stream_builder|data_distributor"
echo -e "Example:$0 -r us-east-1 -c customer_builder"
}
while getopts ":r:c:" opt; do
case $opt in
r) region="$OPTARG";;
c) component="$OPTARG"
if [[ "${c}" != "customer_builder" && "${c}" != "customer_service" && "${c}" != "historic_customer_builder" && "${c}" != "stream_builder" && "${c}" != "data_distributor" ]]; then
usage
exit 1
fi
;;
*) usage
exit 1
;;
esac
done
我尝试使用的主要逻辑并需要帮助:
if [[ "${c}" != "customer_builder" && "${c}" != "customer_service" && "${c}" != "historic_customer_builder" && "${c}" != "stream_builder" && "${c}" != "data_distributor" ]]; then
usage
exit 1
fi
所以在我的测试中,我无法获得强制执行的字符串。
如果输错字符串,我希望得到usage
:
./script.sh -r us-east-1 -c customer-builder
./script.sh -r us-east-1 -c customer
./script.sh -r us-east-1 -c builder
./script.sh -r us-east-1 -c foo_bar
但是,如果我正确输入脚本,我应该会执行该脚本:
./script.sh -r us-east-1 -c customer_builder
./script.sh -r us-east-1 -c customer_service
./script.sh -r us-east-1 -c stream_builder
所以我的问题是你将如何处理和检查正确的字符串输入? 有没有更好的方法来编写我的测试?
答案 0 :(得分:1)
您正在测试错误的参数。 $c
尚未定义,但您刚刚在-c
中保存了$component
个参数。
也就是说,另一个case
声明可能比您的if
条件更简单,并且不依赖于bash
扩展。
case $component in
customer_builder|\
customer_service|\
historic_customer_builder|\
stream_builder|\
data_distributor)
: # Do nothing
;;
*)
usage
exit 1
;;
esac
好了,既然我已经从我的系统中尝试保持POSIX兼容,这里使用if
&#39; s更简单[[...]]
声明模式匹配能力。 (这将在较新版本的bash
中按原样运行;旧版本需要shopt -s extglob
才能启用@(...)
语法。)
if [[ $component != @(customer_builder|customer_service|historic_customer_builder|stream_builder|data_distributor) ]]; then