Question

我使用以下AJAX来调用PHP函数：

 $.ajax({
    url : 'php/jstranslator.php',
    type : 'post',
    data : {'action' : 'campaignnamecheck',
           'newcampaignname' : campaignname,
           'oldcampaignname' : oldcampaignname },
    success : function(result) {
        check = result;
        console.log("campaignnamecheck: " + check);
    },
    error : function(xhr, desc, err) {
        console.log(xhr);
        console.log("Details: " + desc + "\nError:" + err);
    }
});

接收此电话的php如下所示：

if ($_POST['action'] == "campaignnamecheck") {
    $newcampaignname = $_POST['newcampaignname'];
    $oldcampaignname = $_POST['oldcampaignname'];

    campaignnamecheck($newcampaignname, 
                      $oldcampaignname);

}

campaignnamecheck函数如下所示：

function campaignnamecheck($newcampaignname, $oldcampaignname) {
    $conn = conn();
    echo "php oldcampaignname: " . $oldcampaignname;
    // Select any campaigns 
    $campaignsql = "SELECT CampaignName " .
        "FROM campaignstest " .
        "WHERE CampaignName = '" . $newcampaignname . "' ";
    if(!$campaignresult = $conn->query($campaignsql)){
        die('There was an error running the query "' . $campaignsql . '" [' . $conn->error . ']');
    }

    // If the campaign name remained the same as before it is a safe campaign name
    if ($newcampaignname == $oldcampaignname) {
    } else {
        // If the campaign name changed, or if it's a new campaign, then check to see if the name already exists in the database
        if ($campaignresult->num_rows == 0) {
            echo "true";
        } else {
            echo "false";
        }
    }
}

我在apache错误日志中收到的错误如下：

[Wed Mar 07 16:30:00.330318 2018] [:error] PHP Warning:  Missing argument 2 for campaignnamecheck(), called in /var/www/html/test/php/jstranslator.php on line 110 and defined in /var/www/html/test/php/campaignsfuncs.php on line 747
[Wed Mar 07 16:30:00.330779 2018] [:error] PHP Notice:  Undefined variable: oldcampaignname in /var/www/html/test/php/campaignsfuncs.php on line 749

当我在chrome上查看控制台的网络选项卡时，我可以看到您设置的值：

action:campaignnamecheck
newcampaignname:test
oldcampaignname:none

我到底错过了什么？

Answer 1

我不知道为什么这解决了我的问题。但是为了调试我添加了一行：

if ($_POST['action'] == "campaignnamecheck") {
    $newcampaignname = $_POST['newcampaignname'];
    $oldcampaignname = $_POST['oldcampaignname'];
    var_dump($oldcampaignname);

    campaignnamecheck($newcampaignname, 
                      $oldcampaignname);

}

现在它似乎正在发挥作用。

Answer 2

所以我觉得很明显。不知何故，你没有将第二个参数传递给campaignnamecheck()。表示您尚未从$_POST收到。

if ($_POST['action'] == "campaignnamecheck") {
  $newcampaignname = $_POST['newcampaignname'];
  $oldcampaignname = $_POST['oldcampaignname'];
  if(!empty($newcampaignname) && !empty($oldcampaignname)) {
     campaignnamecheck($newcampaignname, $oldcampaignname); 
  }
}

首先，当你编写代码时，你需要检查值是否适合ifs或try catch语句。

并且调试代码也是必不可少的技能

当AJAX正确发送时，PHP无法接收AJAX后期数据

2 个答案: