Question

非常简单的设置，但我根本就没有得到它......

的functions.php

class functions {
    function output_functions() {
        function sendMail($to, $subject, $message){
            //...code...
        }
    }
}

myfile.php

include $_SERVER['DOCUMENT_ROOT'] ."some/subfolders/functions.php";

$myFunction = new functions();
$myFunction->output_functions()->sendMail("mail@mail.com","My Subject","My Message");

我收到了错误：

在null
上调用成员函数sendMail（）

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Answer 1

如果你想按类型（output_functions，input_functions等）对你的函数进行分组，我会为每个函数做一个不同的类。然后，您应该将它们定义为公共或私有。

正如已经说过的那样，嵌套函数不能从外部加入，它们只能在定义它们的函数范围内使用。

Answer 2

你在哪里找到这样的语法？

class Helper_Output {

  static public function sendMail($to, $subject, $message){
            //...code...
        }
}

//and usage: 
Helper_Output::sendMail("mail@mail.com","My Subject","My Message");

Answer 3

class Methods1 {
  public function do1() {
    echo __FUNCTION__ . PHP_EOL;
  }

  public function do2() {
    echo __FUNCTION__ . PHP_EOL;
  }
}

class Methods2 {
  public function do1() {
    echo __LINE__ . PHP_EOL;
  }

  public function do2() {
    echo __LINE__ . PHP_EOL;
  }
}

class Factory {
  public function getMethods1() {
    static $cache = new Methods1;

    return $cache;

  }

  public function getMethods2() {
    static $cache = new Methods2;

    return $cache;

  }
}

用法：

$factory = new Factory;
$factory->getMethods1()->do1();
$factory->getMethods1()->do2();
$factory->getMethods2()->do1();
$factory->getMethods2()->do2();

在类中调用函数函数（PHP）

3 个答案: