长度和信息与格式不同

Question

基本上，我希望format，informat和$22都是format格式的$22变量。但是，当我运行以下代码并检查变量属性时，它指出length为2但informat为$2且data ETHNIC; set ethnicity; format ETHNIC $ 22.; /*the format I need, but it doesn't seem to work as I wanted*/ if ETHNIC='1' then do; ETHNIC='Hispanic or Latino'; end; if ETHNIC='2' then do; ETHNIC='Not Haspanic or Latino'; end; keep SUBJID ETHNIC; run; 为{{1} }}

$22

如何让所有三个成为private copyTableByStatus(table: Table, status: string): Table{ // XXX: Weird, javascript can't deep copy. Object.assign() only creates // shallow copies. There should be something like Object.clone() ... let newTable: Table = JSON.parse(JSON.stringify(table)); newTable.checkins = JSON.parse(JSON.stringify(table.checkins.map( checkin => { checkin.items = JSON.parse(JSON.stringify(checkin.items.filter( item => item.statusOItem == status ))) return checkin; } ))) return newTable; }

Answer 1

由于你已经有长度为2的种族变量，所以需要这个长度。因此，您需要在set语句之前使用length或format语句覆盖该长度。

data ETHNIC; 
 format ETHNIC $ 22.   ;
set ethnicity;

if ETHNIC='1' then do;
    ETHNIC='Hispanic or Latino';
end;
if ETHNIC='2' then do;
    ETHNIC='Not Haspanic or Latino';
end;

run;

Answer 2

因为输入和输入的名称相同;输出字段“ETHNIC”您无法更改长度，因为编译器认为您指的是输入字段。

解决方案：

• 重命名输入字段
• 使用长度，格式＆amp;信息陈述。

代码：

/*Creating dummy data*/
data ethnicity;
input SUBJID $ ETHNIC $;
cards;
A 1
B 1
C 2
;;;
run;
data ETHNIC;        
set ethnicity (rename=(ETHNIC=ETHNIC1)); /*rename ETHNIC to ETHNIC1 to avoid conflict  */
format ETHNIC $ 22.;    /*the format I need, but it doesn't seem to work as I wanted*/
informat ETHNIC $ 22.;  /* Define Informat here*/
length ETHNIC $ 22.;    /* Define Length here*/
    if ETHNIC1='1' then do;
        ETHNIC='Hispanic or Latino';
    end;
    if ETHNIC1='2' then do;
        ETHNIC='Not Haspanic or Latino';
    end;
    keep SUBJID ETHNIC;
run;
/*Check log for table definition*/
proc sql;
describe table ETHNIC;
quit;

输出：

日志：确认字段长度，格式，信息

create table WORK.ETHNIC( bufsize=4096 )
   SUBJID char(8),
   ETHNIC char(22) format=22. informat=22.
  );