Question

我有三个文件， foo.php ， bar.php 和 baz.php ，每个include'd接下来，如下：

foo.php

<?php

$missile_launch_codes = [
    'missileA' => '...',
    'missileB' => '...',
    'missileC' => '...'
];

bar.php

<?php

require('foo.php');

function try_to_launch($launch_code) {
    ...
}

function launch_missile($missile_name) {
    if (in_array($missile_name, $missile_launch_codes)) {
        return try_to_launch($missile_launch_codes[$missile_name]);
    } else {
        return false;
    }
}

baz.php

require('bar.php')   

if (...) {
    launch_missile(...);
}

baz.php 文件需要能够使用launch_missile()，但绝对不能访问$missile_launch_codes。我如何隔离从 foo.php 导入的$missile_launch_codes以使其不受 baz.php 的控制？

Answer 1

你可以做的就是Object-oriented方式：

<强> Missile.php

Class Missile
{

    private $missile_launch_codes = [
        'missileA' => '...',
        'missileB' => '...',
        'missileC' => '...'
    ];

    private function try_to_launch($launch_code) {
        ...
    }

    public function launch_missile($missile_name) {
        if (in_array($missile_name, $this->missile_launch_codes)) {
            return $this->try_to_launch($this->missile_launch_codes[$missile_name]);
        } else {
            return false;
        }
    }

}

Launch.php

include('Missile.php');
Class Launch extends Missile
{
    if (...) {
        $this->launch_missile(...);
    }
}

此处，$missile_launch_codes只能在Missile类声明private时才能访问。

Answer 2

如果我是你，你需要在OOP中制作它。你可以这样做......

foo.php：

class Foo {
    protected function missile_launch_codes() {
         return [
           'missileA' => '...',
           'missileB' => '...',
           'missileC' => '...'
         ];
    }
}

bar.php：

class Bar extends Foo {
   public function try_to_launch($launch_code) {
      ...
   }

   public function launch_missile($missile_name) {
      if (in_array($missile_name, $missile_launch_codes)) {
         return try_to_launch($this->missile_launch_codes[$missile_name]);
      } else {
         return false;
      }
   }
}

baz.php

class Baz extends Bar {
   // you cannot access missile_launch_codes() here
}

尝试更多地了解OOP，以便更多地了解我在这里要说的内容..

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2 个答案: