让我解释一下我想要实现的目标。点击标签1将再次显示按钮,我希望按钮禁用与标签2和标签3相同。
JsFiddle - http://jsfiddle.net/yingchor/xjzutbr9/2/
SELECT CASE WHEN SUM([Dollar Value]) > 100
THEN 'Yes'
ELSE 'No'
END As Promotion
FROM [Table]
WHERE ID IN(1, 3)
我应该如何更改脚本以实现这一目标?
答案 0 :(得分:0)
如果我理解你试试这个:
$('.radio-button').on("click", function(event) {
var this_input = $(this);
if (this_input.attr('checked1') == '1') {
this_input.attr('checked1', '1')
} else {
this_input.attr('checked1', '2')
}
$('.radio-button').prop('checked', false);
if (this_input.attr('checked1') == '1') {
this_input.prop('checked', false);
this_input.attr('checked1', '2');
$('.box').hide(); // Hides button in second click
} else {
this_input.prop('checked', true);
this_input.attr('checked1', '1')
}
});