我正在尝试将表单上传到数据库,该表单使用相同的字段名称作为CMS的一部分。
这是表单(我使用JQuery将div乘以每个产品的选项数量):
<form method="post" enctype="multipart/form-data" action="testing.php">
<div class="OptExtra1">
<h3>Additional Option</h3>
<label for="RESAddType">File type (i.e. “CD” or “Download”)</label>
<input name="RESAddType[]" type="text" id="RESAddType" size="48" class="FW" />
<label for="RESAddTitle">File title (i.e. “Boxed Set of 4 CDs”)</label>
<input name="RESAddTitle[]" type="text" id="RESAddTitle" size="48" class="FW" />
<label for="RESAddFType">File format (As “MP3” // “WORD” // “PDF”)</label>
<input name="RESAddFType[]" type="text" id="RESAddFType" size="48" class="FW" />
<label for="RESAddPrice">File price (Enter as “6.99” – <strong>NO “£” SIGN!</strong>)</label>
<input name="RESAddPrice[]" type="text" id="RESAddPrice" size="48" class="FW" />
<label for="RESAddFName">File name</label>
<input name="RESAddFName[]" type="text" id="RESAddFName" size="48" class="FW" />
<label for="RESAddTxt">File text</label>
<textarea name="RESAddTxt[]" id="RESAddTxt" cols="70" rows="50" class="mceAdvanced"></textarea>
<label for="RESAddSample">File text</label>
<textarea name="RESAddSample[]" id="RESAddSample" cols="70" rows="50" class="mceVSimple"></textarea>
<input type="button" value="Add another option" class="SubmitButton" onclick="inserter()" />
<hr />
</div>
<p><input type="submit" name="submit" value="Add Resource" class="SubmitButton"/><input type="hidden" name="RESCatCode" value="2" /><input type="hidden" name="RESCatSubCode" value="5" /><input type="hidden" name="submitted" value="true" /></p>
这就是我到目前为止的PHP
if(isset($_POST['submitted'])){
$RESCode = 100;
$RESAddType = $_POST['RESAddType'];
$RESAddTitle = htmlentities($_POST['RESAddTitle'], ENT_QUOTES);
$RESAddFType = $_POST['RESAddFType'];
$RESAddPrice = $_POST['RESAddPrice'];
$RESAddFName = $_POST['RESAddFName'];
$RESAddTxt = mysql_real_escape_string($_POST['RESAddTxt']);
$RESAddSample = mysql_real_escape_string($_POST['RESAddSample']);
for ($i=0; $i < count($_POST['RESAddType']); $i++) {
$OptionQuery = mysql_query ("INSERT INTO ResAdd (RESAddCode, RESCode, RESAddType, RESAddTitle, RESAddFType, RESAddPrice, RESAddFName, RESAddTxt, RESAddSample) VALUES ('', '".$RESCode."', '".$RESAddType."', '".$RESAddTitle."', '".$RESAddFType."', '".$RESAddPrice."', '".$RESAddFName."', '".$RESAddTxt."', '".$RESAddSample."');");
}
header("Location: welcome.php");
exit;
}
它有点工作,但只是将“数组”这个词放入数据库中。此外,htmlentities和mysql_real_escape_string帖子不会向数据库上传任何内容。
有什么想法吗?
答案 0 :(得分:2)
你忘记了什么:)
$OptionQuery = mysql_query ("INSERT INTO ResAdd (RESAddCode, RESCode, RESAddType, RESAddTitle, RESAddFType, RESAddPrice, RESAddFName, RESAddTxt, RESAddSample) VALUES ('', '".$RESCode[$i]."', '".$RESAddType[$i]."', '".$RESAddTitle[$i]."', '".$RESAddFType[$i]."', '".$RESAddPrice[$i]."', '".$RESAddFName[$i]."', '".$RESAddTxt[$i]."', '".$RESAddSample[$i]."');");
在上面的代码中查看所有这些$i
。如果你不使用它们,脚本将尝试使用整个数组(并尝试打印或保存数组作为字符串总是导致打印“数组”)。
P.S.I've编辑了我的答案。对于前一个,很抱歉,我误解了代码并发布了错误的答案。
答案 1 :(得分:1)
你需要循环
$cnt=count($_POST['RESAddType']);
for ($counter=0; $counter < $cnt; $counter++)
{
$_POST['RESAddType'][$counter]// to access the value
$_POST['RESAddPrice'][$counter]//
//create your query here
}