我之前尝试过问过这个问题,但说得不好。这是一个新尝试,因为我还没有解决它。
我有一个包含赢家,输家,日期,赢家点数和输家点数的数据集。
对于每一行,我想要两个新列,一个用于获胜者,一个用于失败者,用于显示他们到目前为止得分的数量(作为赢家和输家)。
示例数据:
winner <- c(1,2,3,1,2,3,1,2,3)
loser <- c(3,1,1,2,1,1,3,1,2)
date <- c("2017-10-01","2017-10-02","2017-10-03","2017-10-04","2017-10-05","2017-10-06","2017-10-07","2017-10-08","2017-10-09")
winner_points <- c(2,1,2,1,2,1,2,1,2)
loser_points <- c(1,0,1,0,1,0,1,0,1)
test_data <- data.frame(winner, loser, date = as.Date(date), winner_points, loser_points)
我希望输出为:
winner_points_sum <- c(0, 0, 1, 3, 1, 3, 5, 3, 5)
loser_points_sum <- c(0, 2, 2, 1, 4, 5, 4, 7, 4)
test_data <- data.frame(winner, loser, date = as.Date(date), winner_points, loser_points, winner_points_sum, loser_points_sum)
到目前为止我是如何解决它的方法是做一个for循环,例如:
library(dplyr)
test_data$winner_points_sum_loop <- 0
test_data$loser_points_sum_loop <- 0
for(i in row.names(test_data)) {
test_data[i,]$winner_points_sum_loop <-
(
test_data %>%
dplyr::filter(winner == test_data[i,]$winner & date < test_data[i,]$date) %>%
dplyr::summarise(points = sum(winner_points, na.rm = TRUE))
+
test_data %>%
dplyr::filter(loser == test_data[i,]$winner & date < test_data[i,]$date) %>%
dplyr::summarise(points = sum(loser_points, na.rm = TRUE))
)
}
test_data$winner_points_sum_loop <- unlist(test_data$winner_points_sum_loop)
有任何建议如何解决这个问题?当行号加起来时,查询需要相当长的时间。我已尝试用AVE功能进行详细说明,我可以在一列中将玩家点数作为赢家,但无法弄清楚如何将他们的点数添加为输家。
答案 0 :(得分:2)
winner <- c(1,2,3,1,2,3,1,2,3)
loser <- c(3,1,1,2,1,1,3,1,2)
date <- c("2017-10-01","2017-10-02","2017-10-03","2017-10-04","2017-10-05","2017-10-06","2017-10-07","2017-10-08","2017-10-09")
winner_points <- c(2,1,2,1,2,1,2,1,2)
loser_points <- c(1,0,1,0,1,0,1,0,1)
test_data <- data.frame(winner, loser, date = as.Date(date), winner_points, loser_points)
library(dplyr)
library(tidyr)
test_data %>%
unite(winner, winner, winner_points) %>% # unite winner columns
unite(loser, loser, loser_points) %>% # unite loser columns
gather(type, pl_pts, winner, loser, -date) %>% # reshape
separate(pl_pts, c("player","points"), convert = T) %>% # separate columns
arrange(date) %>% # order dates (in case it's not)
group_by(player) %>% # for each player
mutate(sum_points = cumsum(points) - points) %>% # get points up to that date
ungroup() %>% # forget the grouping
unite(pl_pts_sumpts, player, points, sum_points) %>% # unite columns
spread(type, pl_pts_sumpts) %>% # reshape
separate(loser, c("loser", "loser_points", "loser_points_sum"), convert = T) %>% # separate columns and give appropriate names
separate(winner, c("winner", "winner_points", "winner_points_sum"), convert = T) %>%
select(winner, loser, date, winner_points, loser_points, winner_points_sum, loser_points_sum) # select the order you prefer
# # A tibble: 9 x 7
# winner loser date winner_points loser_points winner_points_sum loser_points_sum
# * <int> <int> <date> <int> <int> <int> <int>
# 1 1 3 2017-10-01 2 1 0 0
# 2 2 1 2017-10-02 1 0 0 2
# 3 3 1 2017-10-03 2 1 1 2
# 4 1 2 2017-10-04 1 0 3 1
# 5 2 1 2017-10-05 2 1 1 4
# 6 3 1 2017-10-06 1 0 3 5
# 7 1 3 2017-10-07 2 1 5 4
# 8 2 1 2017-10-08 1 0 3 7
# 9 3 2 2017-10-09 2 1 5 4
答案 1 :(得分:1)
我终于理解了你想要的东西。我采取了一种方法,在每个时间点获得每个玩家的累积积分,然后将其加入原始的winner <- c(1,2,3,1,2,3,1,2,3)
loser <- c(3,1,1,2,1,1,3,1,2)
date <- c("2017-10-01","2017-10-02","2017-10-03","2017-10-04","2017-10-05","2017-10-06","2017-10-07","2017-10-08","2017-10-09")
winner_points <- c(2,1,2,1,2,1,2,1,2)
loser_points <- c(1,0,1,0,1,0,1,0,1)
test_data <- data.frame(winner, loser, date = as.Date(date), winner_points, loser_points)
library(dplyr)
library(tidyr)
cum_points <- test_data %>%
gather(end_game_status, player_id, winner, loser) %>%
gather(which_point, how_many_points, winner_points, loser_points) %>%
filter(
(end_game_status == "winner" & which_point == "winner_points") |
(end_game_status == "loser" & which_point == "loser_points")) %>%
arrange(date = as.Date(date)) %>%
group_by(player_id) %>%
mutate(cumulative_points = cumsum(how_many_points)) %>%
mutate(cumulative_points_sofar = lag(cumulative_points, default = 0))
select(player_id, date, cumulative_points)
output <- test_data %>%
left_join(cum_points, by = c('date', 'winner' = 'player_id')) %>%
rename(winner_points_sum = cumulative_points_sofar) %>%
left_join(cum_points, by = c('date', 'loser' = 'player_id')) %>%
rename(loser_points_sum = cumulative_points_sofar)
output
数据框。
pip install https://github.com/nithinmurali/pygsheets/archive/staging.zip
答案 2 :(得分:0)
与previous question of the OP的区别在于OP现在要求每个玩家到目前为止得分的累积总和,即在实际日期之前。此外,样本数据集现在包含唯一标识每一行的date
列。
因此,my previous approach也可以在这里使用,并进行一些修改。下面的解决方案将数据从宽格式转换为长格式,从而同时重塑两个值变量,计算每个玩家ID的累积总和,最后再次从长格式再格式化为宽格式。为了只计算在实际日期之前得分的点数,这些行会滞后一行。
请注意,winner
和loser
列包含相应的播放器ID。
library(data.table)
cols <- c("winner", "loser")
setDT(test_data)[
# reshape multiple value variables simultaneously from wide to long format
, melt(.SD, id.vars = "date",
measure.vars = list(cols, paste0(cols, "_points")),
value.name = c("id", "points"))][
# rename variable column
, variable := forcats::lvls_revalue(variable, cols)][
# order by date and cumulate the lagged points by id
order(date), points_sum := cumsum(shift(points, fill = 0)), by = id][
# reshape multiple value variables simultaneously from long to wide format
, dcast(.SD, date ~ variable, value.var = c("id", "points", "points_sum"))]
date id_winner id_loser points_winner points_loser points_sum_winner points_sum_loser 1: 2017-10-01 1 3 2 1 0 0 2: 2017-10-02 2 1 1 0 0 2 3: 2017-10-03 3 1 2 1 1 2 4: 2017-10-04 1 2 1 0 3 1 5: 2017-10-05 2 1 2 1 1 4 6: 2017-10-06 3 1 1 0 3 5 7: 2017-10-07 1 3 2 1 5 4 8: 2017-10-08 2 1 1 0 3 7 9: 2017-10-09 3 2 2 1 5 4