Question

我有两种形式。我想在移动设备进入会话的第二个节目中显示mobile。此处会话ID已显示，但mobile未显示。

第1页/页：sign.php

<?php session_start();
<?php $r=session_id();?>
<?php include('include/config.php');?>
<form class="ff" action="signc.php" method="POST">
<a>Enter Your Mobile No.</a>
<input type="text" id="inp" name="mobile" required>
</br></br>
<input type="submit" id="btn" value="continue">
</form>

signc.php

<?php session_start();
<?php $r=session_id();?>
<?php include('include/config.php');?>
$sql = mysqli_query($connection, "INSERT INTO `mobile_message`  SET `mobile` = '$mobile'");

 if($sql){

    $_SESSION['s']= "OTP sent to your mobile.";
        header('Location:sign2.php');

} else{
    $_SESSION['e']=  "Could not able to execute. ";
    header('Location:sign.php');

}

第二张表格/页：sign2.php

<?php session_start();
<?php $r=session_id();?>
<?php include('include/config.php');?>
<form class="ff" action="sign2c.php" method="POST">
<a class="ase" >Enter Your Mobile No.</a>
<?php
    $cid=$_SESSION['cid'];
    $_q=mysqli_query($connection, "select * from mobile_message where mobile='$cid'");
    $_t=mysqli_fetch_array($_q);
    echo $_t['mobile'];
    echo $r;
    ?>
</br></br>
<a class="ase" >Enter Password</a>
<input type="text" id="inp" name="otp" required>
</br>
<input type="submit" id="btn" value="continue">
</form>

<!--hgfh-->

echo $_t['mobile'];没有显示任何内容

echo $r;显示cgvk2tla6r14h38i2v7dlhkj80

Answer 1

只需在btn_txt = 'Check'; check() { if (this.btn_txt == 'Check') { //do some logic this.btn_txt = 'Next'; } else { console.log('go to next page'); } }

中添加这两行

signc.php

更正后的$cid=$_POST['mobile']; $_SESSION['cid']=$cid;将会像

一样

signc.php

在第二页转发表单中显示输入名称

1 个答案: