Question

我有一个文本文件（由fortran程序创建），格式如下：

  -12.7414170939064                1
  -11.5491412174559                2
  -9.71491476113225                3
  -7.58225748434563                4
  -7.31861308884334                5
  -6.34960810316479                6
  -4.80519553745030                7
  -3.90146854139010                8
  -3.24840468213061                9
  -3.00329610180486               10

每行以几个空格开头。然后浮动。接下来是一些空格，然后是整数。我想将每行的第一个浮点数存储到一个浮点数组中，而不是其他任何内容。第二列中的整数无关紧要。我如何在python中执行此操作？

Answer 1

file = open('test.txt', 'r') #open file for reading

list_with_floats = []
for line in file:
    temp = line.split() #create a list with the float and the int as list elements
    list_with_floats.append(temp[0]) #store the float in the list

print(list_with_floats)

['-12.7414170939064', '-11.5491412174559', '-9.71491476113225', '-7.58225748434563', '-7.31861308884334', '-6.34960810316479', '-4.80519553745030', '-3.90146854139010', '-3.24840468213061', '-3.00329610180486']

将一列从测试文件保存到python中的数组中

1 个答案: