Question

existingJsObj = {"a": [1,2,3,4], "b":[11,22,33,44]}

我想将此javascript转换为其中没有数组项的内容，如下面的

desiredJsObj = [{"a":1, "b":11},{"a":2,"b":22},{"a":3, "b":33},{"a":4, "b":44}]

Answer 1

我会这样做：

const income = {"a": [1,2,3,4], "b":[11,22,33,44]};

const res = income.a.map((a, i) => ({ a: a, b: income.b[i] }));

这假设“a”长度等于“b”长度。

Answer 2

您可以在为结果使用新数组和对象时迭代键和值。

var object = { a: [1, 2, 3, 4], b: [11, 22, 33, 44] },
    array = Object.keys(object).reduce(function (r, k) {
        object[k].forEach(function (v, i) {
            (r[i] = r[i] || {})[k] = v;
        });
        return r;
    }, []);

console.log(array);

.as-console-wrapper { max-height: 100% !important; top: 0; }

Answer 3

试试这个

existingJsObj = {"a": [1,2,3,4], "b":[11,22,33,44]}
desiredJsObj = []
keys = Object.keys(existingJsObj);
existingJsObj[keys[0]].forEach((val, index) => {
    value = {};
    keys.forEach((key, i) => value[key] = existingJsObj[key][index])
    desiredJsObj.push(value)
})

如何在没有重复条目的情况下将javascript对象展开到Json对象中

3 个答案: