REGEXP_REPLACE查询oracle

时间:2017-11-10 09:27:25

标签: sql oracle regexp-replace regexp-like

我有一个类似的文字。

    ( ( tt.TRAN_TYPE IN
       ( SELECT RULE_VALUE FROM GP_RULE_VALUE WHERE RULE_ID=1332 )
   AND tt.CONTRACT IN
       ( SELECT RULE_VALUE FROM GP_RULE_VALUE WHERE RULE_ID=1333 )
   AND tt.CUSTOMER_STATE NOT IN
       ( SELECT RULE_VALUE FROM GP_RULE_VALUE WHERE RULE_ID=1334)
   AND tt.COT_IND IN
       ( SELECT RULE_VALUE FROM GP_RULE_VALUE WHERE RULE_ID=1335 ))
OR     ( tt.TRAN_TYPE IN
        ( SELECT RULE_VALUE FROM GP_RULE_VALUE WHERE RULE_ID=1336 )
   AND tt.WHLSE_COT NOT IN
       ( SELECT RULE_VALUE FROM GP_RULE_VALUE WHERE RULE_ID=1337 )
   AND tt.COT_IND IN
       ( SELECT RULE_VALUE FROM GP_RULE_VALUE WHERE RULE_ID=1338 )) )

我需要用条件tt替换tt。*。* IS NOT NULL和tt。* ...如下所示。

( 
          ( (tt.TRAN_TYPE IS NOT NULL AND tt.TRAN_TYPE IN ( SELECT RULE_VALUE FROM GP_RULE_VALUE WHERE RULE_ID=1332 ))
          AND (tt.CONTRACT IS NOT NULL AND tt.CONTRACT IN ( SELECT RULE_VALUE FROM GP_RULE_VALUE WHERE RULE_ID=1333))
          AND (tt.CUSTOMER_STATE IS NOT NULL AND tt.CUSTOMER_STATE NOT IN ( SELECT RULE_VALUE FROM GP_RULE_VALUE WHERE RULE_ID=1334))
          AND (tt.COT_IND IS NOT NULL AND tt.COT_IND IN ( SELECT RULE_VALUE FROM GP_RULE_VALUE WHERE RULE_ID=1335)))
        OR ( (tt.TRAN_TYPE IS NOT NULL AND tt.TRAN_TYPE IN ( SELECT RULE_VALUE FROM GP_RULE_VALUE WHERE RULE_ID=1336))
          AND (tt.WHLSE_COT IS NOT NULL AND tt.WHLSE_COT NOT IN ( SELECT RULE_VALUE FROM GP_RULE_VALUE WHERE RULE_ID=1337))
          AND (tt.COT_IND IS NOT NULL AND tt.COT_IND IN ( SELECT RULE_VALUE FROM GP_RULE_VALUE WHERE RULE_ID=1338))) 
          )

请提供REGEXP_REPLACE或ORACLE中的任何其他技巧。

注意:对我来说,主要的挑战似乎是取代查询顺序保持正确的方式(即正确打开和关闭括号)

1 个答案:

答案 0 :(得分:0)

试试这个。

SELECT REGEXP_REPLACE (yourtext, 'tt\.(.+) ', 'tt.\1 IS NOT NULL AND tt.\1 ')
  FROM yourtable;