Question

我正在尝试将libxml2移植到android.When我使用带空格的文件路径（例如path =＆＃34; / storage / emulated / 0 / sdcard / New XML.xml＆＃34;），打开xml文件失败。但是如果我使用不带空格的路径（例如＆＃34; / storage） /emulated/0/sdcard/NewXML.xml"。解析文件成功。请帮我解决这个问题。

以下是示例代码：

#include <stdio.h>
#include <libxml/xmlreader.h>

static void
processNode(xmlTextReaderPtr reader) {
    const xmlChar *name, *value;

    name = xmlTextReaderConstName(reader);
    if (name == NULL)
    name = BAD_CAST "--";

    value = xmlTextReaderConstValue(reader);

    printf("%d %d %s %d %d", 
        xmlTextReaderDepth(reader),
        xmlTextReaderNodeType(reader),
        name,
        xmlTextReaderIsEmptyElement(reader),
        xmlTextReaderHasValue(reader));
    if (value == NULL)
    printf("\n");
    else {
        if (xmlStrlen(value) > 40)
            printf(" %.40s...\n", value);
        else
        printf(" %s\n", value);
    }
}

static void streamFile(const char *filename) {
    xmlTextReaderPtr reader;
    int ret;

    reader = xmlReaderForFile(filename, NULL, 0);
    if (reader != NULL) {
        ret = xmlTextReaderRead(reader);
        while (ret == 1) {
            processNode(reader);
            ret = xmlTextReaderRead(reader);
        }
        xmlFreeTextReader(reader);
        if (ret != 0) {
            fprintf(stderr, "%s : failed to parse\n", filename);
        }
    } else {
        fprintf(stderr, "Unable to open %s\n", filename);
    }
}

int main() {
    const char path[64] = "/storage/emulated/0/sdcard/New XML.xml"

    streamFile(path);

    xmlCleanupParser();
    xmlMemoryDump();

    return(0);
}

Answer 1

对您的空间进行编码......

xmlReaderForFile filename：文件或URL

Answer 2

您需要在文件名中转义空格。试试

bazel query

android NDK fopen与空间失败的路径

2 个答案: