Question

在Android应用程序中，如何根据用户说的内容执行不同的Java类。例如，用户单击按钮并说1.应用程序应执行名为1的Java代码。

Answer 1

好吧，关于执行：

如果你有一个值为“One”的String（从任何地方）你可以查找一个具有相同名称的类并通过Reflection执行它的方法，或者如果确定了所有选项，你可以将对象映射到字符串，两种解决方案如下：

package classes;
public class One {
   public void doThings() {}
   public void doThings(String xx) {}
}

public static void main(String[] args){
    String className = "One"; //Imagine that it come from Voice-To-Text
    Class<?> clazz = Class.getDeclaredClass("classes." + className);
    Method doThings = clazz.getDeclaredMethod("doThings");
    Method doThingsWithArgs = clazz.getDeclaredMethod("doThings", String.class);
    Object instance = clazz.newInstance();
    doThings.invoke(instance);
    doThingsWithArgs.invoke(instance, "String as argument");
}

您还可以为所有实施者共享界面：

public interface DoThings {
   void doThings() {}
   void doThings(String xx) {}
}

package classes;
public class One implements DoThings {
   public void doThings() {}
   public void doThings(String xx) {}
}

public static void main(String[] args){
    String className = "One"; //Imagine that it come from Voice-To-Text
    Class<?> clazz = Class.getDeclaredClass("classes." + className);
    DoThings instance = (DoThings) clazz.newInstance();
    instance.doThings();
    instance.doThings("String as argument");
}

地图解决方案如下：

public static void main(String[] args){
    Map<String, DoThings> calls = new HashMap<String, DoThings>();
    calls.add("One", new One());
    calls.add("Second", new One());

    String className = "One"; //Imagine that it come from Voice-To-Text

    DoThings instance = (DoThings) calls.get(className);
    instance.doThings();
    instance.doThings("String as argument");
}

根据用户音频输入执行代码

1 个答案: