Question

我正在使用RxJava进行改造。我想知道如何在请求失败或成功时检索请求发送的BODY / RAW。

这是我的控制器调用API：

ChatMessage body = new ChatMessage();
    ...
    //configuration of body variable is omitted.
    ...

chatController.sendMessage(body).subscribe(this::onSendMessageSuccess, this::onSendMessageError);

这些是获得答案的方法：

private void onSendMessageSuccess(ChatRestResponse response) {
   // How can I get the "ChatMessage body" sent in at first by the re
}

private void onSendMessageError(Throwable throwable) {
     // How can I get the "ChatMessage body" sent in at first by the request       
}

我想知道如何获取用于发出请求的ChatMessage类。

仅供参考

这是我的界面：

@Headers({
     "Accept: application/json",
     "Content-Type: application/json"
})
@POST(URL)
Observable<ChatRestResponse> sendMessage(
     @Header("Authorization") String token,
     @Body ChatMessage body);

这是我的控制器，它调用api：

public Observable<ChatRestResponse> sendMessage(ChatMessage body) {
     String accessToken = mPref.getAccesToken();

     return mChatApi.sendMessage(accessToken , body)
         .subscribeOn(Schedulers.newThread())
         .observeOn(AndroidSchedulers.mainThread());
}

Answer 1

Brother On Failure没有任何机构存在回应。只会有一些代码与它所面临的错误相关联。像404等但是，如果您正在谈论自己的服务器响应失败。就像您通过Retrofit从您的应用程序登录到您的帐户一样。如果您输入了错误的凭据，互联网和与服务器的连接都可以，即使这样，响应也将运行函数onResponce()。但是在这里，您可以检查服务器将发送的与类型或错误相关联的服务器内部错误。

call.enqueue(new Callback<LoginResponse>() {
                    @Override
                    public void onResponse(Call<LoginResponse> call, Response<LoginResponse> response) {
                        if (response.code == HttpURLConnection.HTTP_OK) {
                            //All is well
                            // you can get body here as 
                            String token = responce.body().getToken();
                            //etc
                        } else {
                           //Something went wrong like password etc
                           //You can check the body here also in case of failure
                           //Which is due to some internal server error
                           //because of wrong credentials
                           //But this response is in failure and also have a body 
                           //I guess this is what u want
                           String failuerToken = responce.getBody().getAccessToken();
                            new AlertDialog.Builder(LoginActivity.this)
                                    .setMessage("Invalid Credentials")
                                    .setCancelable(false)
                                    .setPositiveButton("Try Again", null)
                                    .show();
                        }
                    }

                    @Override
                    public void onFailure(Call call, Throwable t) {
                        showProgress(false);

                        new AlertDialog.Builder(LoginActivity.this)
                                .setMessage("Unable to reach server")
                                .setCancelable(false)
                                .setPositiveButton("Try Again", null)
                                .show();
                        call.cancel();
                    }
                });

请注意

LoginResponse

是我自己的班级

public class LoginResponse {
    @SerializedName("access_token")
    @Expose
    public String accessToken;
    @SerializedName("token_type")
    @Expose
    public String tokenType;
    @SerializedName("expires_in")
    @Expose
    public Integer expiresIn;
}

<强>更新

Call<LoginResponse> call = apiInterface.Login(requestData);

请参阅我使用requestData发送数据。解决问题的唯一方法是创建一个单独的包名urils，创建一个类RequestData并在其中放入一些静态变量。

public class RequestData {
    public static String username;
    public static String password;
    public static String email;
    public static Int age;
    //etc
}

像这样设置变量值

RequestData.username = "abcd";
RequestData.password = "abcd";
RequestData.email = "abcd@email.com";
RequestData.age = 20";

然后通过api call发送数据。

失败后，使用此类从中访问以前的数据并分别在UI上显示。

如何在失败时获得改装请求的正文？

1 个答案: