我有一个像这样的数组
Array
(
[1_DAY_2017] => Array
(
[SAMSUNG] => Array
(
[0] => 549
[1] => 199
[2] => 999
)
[XIAOMI] => Array
(
[0] => 199
[1] => 2999
[2] => 499
)
)
[2_DAY_2017] => Array
(
[SAMSUNG] => Array
(
[0] => 699
[1] => 999
)
[LENOVO] => Array
(
[0] => 280
[1] => 2550
[2] => 849
)
)
[3_DAY_2017] => Array
(
[OPPO] => Array
(
[0] => 500
[1] => 599
)
[SAMSUNG] => Array
(
[0] => 799
)
)
[4_DAY_2017] => Array
(
[SAMSUNG] => Array
(
[0] => 1299
[1] => 499
[2] => 799
[3] => 2500
)
[OPPO] => Array
(
[0] => 299
[1] => 349
[2] => 499
)
)
[5_DAY_2017] => Array
(
[XIAOMI] => Array
(
[0] => 500
[1] => 270
[2] => 340
)
[VIVO] => Array
(
[0] => 4599
[1] => 299
)
)
[6_DAY_2017] => Array
(
[VIVO] => Array
(
[0] => 240
[1] => 1899
[2] => 759
[3] => 530
)
[OPPO] => Array
(
[0] => 999
)
)
[7_DAY_2017] => Array
(
[OPPO] => Array
(
[0] => 300
[1] => 252
[2] => 1290
)
[LENOVO] => Array
(
[0] => 570
[1] => 1300
[2] => 666
)
)
)
从此我想得到一个数组
$output= [SAMSUNG => 9341, XIAOMI => 4807]
此处每个项目都包含嵌套数组中项目的总和。
目前我的解决方案每个循环都包含2个以上但是有没有办法优化这个?
答案 0 :(得分:2)
您可以使用array_sum,array_map和array_column函数来获取结果
array_sum(array_map('array_sum', array_column($a, 'SAMSUNG')))
答案 1 :(得分:1)
使用单array_reduce
个功能:
// $arr is your initial array
$result = array_reduce($arr, function($r, $v){
if (isset($v['SAMSUNG'])) $r['SAMSUNG'] += array_sum($v['SAMSUNG']);
if (isset($v['XIAOMI'])) $r['XIAOMI'] += array_sum($v['XIAOMI']);
return $r;
}, ['SAMSUNG' => 0, 'XIAOMI' => 0]);
答案 2 :(得分:0)
$sumArray = array();
foreach ($YourArray as $k=>$subArray) {
foreach ($subArray as $id=>$value) {
$sumArray[$id]+=$value;
}
}
print_r($sumArray);