Question

感谢您的回答！

这是一个编辑：

SELECT 'SYSA', 
   t1.lieu_stkph_cd, 
   Sum (t1.mt_pnu_cpta_dev_rep), 
   Sum (t2.mt_util_dev_rep) 
FROM   (SELECT a.id_auto, a.dt_art, c.lieu_stkph_cd, 
           a.mt_pnu_cpta_dev_rep 
    FROM   prod_v_ec_dossier_a_sysa c 
           INNER JOIN db_ftg_srs_prod_v.v_autorisation_a a 
                   ON a.id_doss = c.dosscta_no 
                      AND a.cd_prd_cpta = c.prct_no 
                      AND a.cd_entite_cpta = c.entite_cd 
    WHERE  c.pma_cd = '') AS t1
LEFT JOIN (SELECT a.id_auto, a.dt_art, c.lieu_stkph_cd, 
           b.mt_util_dev_rep 
    FROM   prod_v_ec_dossier_a_sysa c 
           INNER JOIN db_ftg_srs_prod_v.v_autorisation_a a 
                   ON a.id_doss = c.dosscta_no 
                      AND a.cd_prd_cpta = c.prct_no 
                      AND a.cd_entite_cpta = c.entite_cd 
           INNER JOIN db_ftg_srs_prod_v.v_utilisation_a b 
                      ON a.dt_art = b.dt_art 
                      AND a.id_auto = b.id_auto 
    WHERE  c.pma_cd = '') AS t2 
             ON  T1.id_auto = t2.id_auto 
            and T1.dt_art = T2.dt_art and t1.lieu_stkph_cd = t2.lieu_stkph_cd
GROUP  BY 1, 
          2

这是此查询的结果：

LIEU_STKPH_CD PNU金额利用金额
1 200€ 250€

这不准确，我解释说：

db_ftg_srs_prod_v.v_autorisation_a链接到db_ftg_srs_prod_v.v_utilisation_a和
- ID_AUTO
- DT_ART
但我可以为X UTILIZATION设置1个ID_AUTO，因此使用此查询我将乘以PN使用PNU量，这是不正确的

授权表

ID_AUTO PNU金额
1 100€

利用表

ID_AUTO ID_UTLIZATION利用金额
1 1 100€
1 2 150€

所以我必须将这些值分开：

预期结果

LIEU_STKPH_CD PNU金额利用金额
1 100€ 250€

你有什么想法吗？

提前致谢
克里斯托夫

Answer 1

在这里对你的数据关系进行大量猜测。您应该使用带有JOIN的实际ON子句来加入，以解释如何将这两个子查询组合在一起。类似的东西：

SELECT 'SYSA', 
       t1.lieu_stkph_cd, 
       Sum (t1.mt_pnu_cpta_dev_rep), 
       Sum (t2.mt_util_dev_rep) 
FROM   (SELECT c.lieu_stkph_cd, 
               a.mt_pnu_cpta_dev_rep 
        FROM   prod_v_ec_dossier_a_sysa c 
               INNER JOIN db_ftg_srs_prod_v.v_autorisation_a a 
                       ON a.id_doss = c.dosscta_no 
                          AND a.cd_prd_cpta = c.prct_no 
                          AND a.cd_entite_cpta = c.entite_cd 
        WHERE  c.pma_cd = '') AS t1
   INNER JOIN (SELECT c.lieu_stkph_cd, 
               b.mt_util_dev_rep 
        FROM   prod_v_ec_dossier_a_sysa c 
               INNER JOIN db_ftg_srs_prod_v.v_autorisation_a a 
                       ON a.id_doss = c.dosscta_no 
                          AND a.cd_prd_cpta = c.prct_no 
                          AND a.cd_entite_cpta = c.entite_cd 
               INNER JOIN db_ftg_srs_prod_v.v_utilisation_a b 
                       ON a.dt_art = b.dt_art 
                          AND a.id_auto = b.id_auto 
        WHERE  c.pma_cd = '') AS t2 
    ON T1.lieu_stkph_cd = t2.lieu_stkph_cd
GROUP  BY 1, 
          2

Answer 2

你的第一个查询是好的，因为你做了

 SELECT ( select ... ) as field 1, 
        ( select ... ) as field 2,

但是你的第二个你正在进行交叉加入

 SELECT *
 FROM ( select ... ) as query1,
      ( select ... ) as query2

使用query1 x query2 rows

创建查询

你想：

 SELECT query.*
 FROM ( SELECT ( select ... ) as field1,
               ( select ... ) as field2
        .....
      ) as query

Answer 3

有几种方法可以摆脱相乘的值，例如：在加入之前聚合

SELECT 'SYSA', 
   t1.lieu_stkph_cd, 
   t1.mt_pnu_cpta_dev_rep, 
   t2.mt_util_dev_rep 
FROM   (SELECT a.id_auto, a.dt_art, c.lieu_stkph_cd, 
           a.mt_pnu_cpta_dev_rep 
    FROM   prod_v_ec_dossier_a_sysa c 
           INNER JOIN db_ftg_srs_prod_v.v_autorisation_a a 
                   ON a.id_doss = c.dosscta_no 
                      AND a.cd_prd_cpta = c.prct_no 
                      AND a.cd_entite_cpta = c.entite_cd 
    WHERE  c.pma_cd = '') AS t1
LEFT JOIN (SELECT a.id_auto, a.dt_art, c.lieu_stkph_cd, 
           Sum(b.mt_util_dev_rep) AS mt_util_dev_rep 
    FROM   prod_v_ec_dossier_a_sysa c 
           INNER JOIN db_ftg_srs_prod_v.v_autorisation_a a 
                   ON a.id_doss = c.dosscta_no 
                      AND a.cd_prd_cpta = c.prct_no 
                      AND a.cd_entite_cpta = c.entite_cd 
           INNER JOIN db_ftg_srs_prod_v.v_utilisation_a b 
                      ON a.dt_art = b.dt_art 
                      AND a.id_auto = b.id_auto 
    WHERE  c.pma_cd = ''
    GROUP  BY 1, 
          2          ) AS t2 
             ON  T1.id_auto = t2.id_auto 
            AND T1.dt_art = T2.dt_art AND t1.lieu_stkph_cd = t2.lieu_stkph_cd

但似乎您不需要加入两个派生表，这应该返回相同的结果：

SELECT 'SYSA', 
   t1.lieu_stkph_cd, 
   -- this value is multiplied by the number of rows 
   -- so simply divide by that number to revert the multiplication 
   Sum (a.mt_pnu_cpta_dev_rep) / Count(*), 
   Sum (b.mt_util_dev_rep) 
FROM prod_v_ec_dossier_a_sysa c 
JOIN db_ftg_srs_prod_v.v_autorisation_a a 
  ON a.id_doss = c.dosscta_no 
AND a.cd_prd_cpta = c.prct_no 
AND a.cd_entite_cpta = c.entite_cd 
JOIN db_ftg_srs_prod_v.v_utilisation_a b 
  ON a.dt_art = b.dt_art 
 AND a.id_auto = b.id_auto 
WHERE  c.pma_cd = ''
GROUP  BY 1, 
          2

Teradata - 错误2646优化查询

3 个答案: