Question

我有两张桌子：

words表：

+----+-------+------+
| id | word  | lang |
+----+-------+------+
|  1 | uña   | es   |
|  2 | two   | en   |
|  3 | three | en   |
|  4 | four  | en   |
+----+-------+------+

stop_words表：

+----+------+------+
| id | word | lang |
+----+------+------+
|  1 | una  | es   |
|  2 | one  | en   |
+----+------+------+

我需要从words表中选择一个单词，其中单词不在stop_words表中

如果我尝试以下查询，结果为空，因为uña来自 words与una

中的stop_words匹配

SELECT  *
FROM words a WHERE word LIKE  'uñ%' AND lang = 'es'
AND NOT EXISTS( Select *
    FROM stop_words as b WHERE a.word = b.word AND lang = 'es'

）

如果我尝试使用BINARY，结果似乎没问题但是如果不使用相同的情况则失败（例如：Uñ代替uñ ）

SELECT  *
FROM words a WHERE word LIKE BINARY 'Uñ%'  AND lang = 'es'
AND NOT EXISTS( Select *
    FROM stop_words as b WHERE BINARY a.word = BINARY b.word AND lang = 'es'
)

我将utf8mb4_unicode_ci用于数据库，表格和列。

知道如何解决这个问题吗？

Answer 1

SELECT id, word, lang 
FROM words 
WHERE BINARY word NOT IN (Select BINARY word FROM stop_words);

结果：

+----+-------+------+
| id | word  | lang |
+----+-------+------+
|  1 | uña   | es   |
|  2 | two   | en   |
|  3 | three | en   |
|  4 | four  | en   |
+----+-------+------+

使用utf8_unicode_ci表格

编辑： 对于同样的情况

SELECT  id, word, lang 
FROM words 
WHERE BINARY LOWER(word) NOT IN (Select BINARY LOWER(word) FROM stop_words);

Mysql SELECT unicode字符

1 个答案: