输出应该是这样的
S/NO. MONTH | CIVIL |CRIMINAL | TOTAL
1 JANUARY
2 FEBRUARY
3 MARCH
4 APRIL
5 MAY
6 JUNE
7 JULY
8 AUGUST
9 SEPTEMBER
10 OCTOBER
11 NOVEMBER
12 DECEMBER
GRAND TOTAL
SELECT JUD_CASE_FILED_MONTH , (SELECT COUNT(JUD_CASE_CATEGORY) FROM[hospitaldb].[dbo].[CF_CASE_REGISTER] WHERE JUD_CASE_CATEGORY ='CIVIL CASES' AND JUD_CASE_FILED_MONTH LIKE '%BER%') as CIVIL,(SELECT COUNT(JUD_CASE_CATEGORY) FROM[hospitaldb].[dbo].[CF_CASE_REGISTER] WHERE JUD_CASE_CATEGORY ='CRIMIMAL CASES'AND JUD_CASE_FILED_MONTH LIKE '%BER%') as CRIMINAL
FROM [hospitaldb].[dbo].[CF_CASE_REGISTER]
GROUP BY JUD_CASE_FILED_MONTH
Union all
select 'SUM' JUD_CASE_CATEGORY, COUNT(JUD_CASE_CATEGORY)
from [hospitaldb].[dbo].[CF_CASE_REGISTER]
我想显示月份,案例类别(民事和刑事)以及在特定月份注册的所有案例类别的总数。获得给定月份中所有案例类别的总和和数量。
答案 0 :(得分:0)
试试这个:
SELECT
JUD_CASE_FILED_MONTH ,
SUM(CASE WHEN JUD_CASE_CATEGORY = 'CIVIL CASES' THEN 1 ELSE 0 END AS 'CIVIL CASES',
SUM(CASE WHEN JUD_CASE_CATEGORY = 'CRIMIMAL CASES' THEN 1 ELSE 0 END AS 'CRIMIMAL CASES',
COUNT(*) AS Total
FROM [hospitaldb].[dbo].[CF_CASE_REGISTER]
WHERE JUD_CASE_FILED_MONTH LIKE '%BER%'
GROUP BY JUD_CASE_FILED_MONTH