我一直在努力让突变发挥作用。 鉴于此GraphQL架构,任何人请可以帮助我创建一个简单的创建用户变异吗?我不明白我错过了什么。我得到它从GraphQL服务器抛出400错误,它不会触发解析功能。
var userType = new GraphQLObjectType({
name: 'User',
description: 'User creator',
fields: () => ({
id: {
type: new GraphQLNonNull(GraphQLString),
description: 'The id of the user.'
},
email: {
type: GraphQLString,
description: 'The email of the user.'
},
business: {
type: GraphQLString,
description:
'The name of the business of the user as the app refers to it.'
},
businessDisplayName: {
type: GraphQLString,
description: 'The name of the business of the user as they typed it in.'
},
trips: {
type: new GraphQLList(tripType),
description: 'The trips of the user, or an empty list if they have none.',
resolve: (user, params, source, fieldASTs) => {
var projections = infoToProjection(fieldASTs)
return Trip.find(
{
_id: {
// to make it easily testable
$in: user.trips.map(id => id.toString())
}
},
projections,
function(err, docs) {
return docs
}
)
}
}
})
})
var schema = new GraphQLSchema({
query: new GraphQLObjectType({
name: 'root',
fields: {
trips: {
type: new GraphQLList(tripType),
resolve: function() {
return Trip.find({})
}
},
users: {
type: new GraphQLList(userType),
resolve: function() {
return User.find({})
}
},
user: {
type: userType,
args: {
id: {
name: 'id',
type: new GraphQLNonNull(GraphQLString)
}
},
resolve: (root, { id }, source, fieldASTs) => {
return User.findOne(
{ _id: id },
infoToProjection(fieldASTs),
function(err, doc) {
return doc
}
)
}
},
trip: {
type: tripType,
args: {
id: {
name: 'id',
type: new GraphQLNonNull(GraphQLString)
}
},
resolve: (root, { id }, source, fieldASTs) => {
var projections = infoToProjection(fieldASTs)
return Trip.findOne({ _id: id }, projections, function(err, doc) {
return doc
})
}
}
}
}),
// mutation
mutation: new GraphQLObjectType({
name: 'Mutation',
fields: {
createUser: {
name: 'createUser',
type: userType,
args: {
input: { type: new GraphQLInputObjectType({
name: 'user',
fields: {
business: { type: GraphQLString },
email: { type: GraphQLString },
businessDisplayName: { type: GraphQLString }
}
})
}},
resolve: (parentValue, args) => {
let user = new User({ ...args.input })
user.save()
return user
}
}
})
})
export var getProjections = infoToProjection
export default schema
这适用于使用以下查询或突变的GraphiQL:
mutation {
createUser(input:{business:"business", email: "e@mai.l", businessDisplayName: "businessDN"}) {
id
email
business
businessDisplayName
}
}
fragment UserFragment on User {
id
business
businessDisplayName
trips{
title
}
}
{
hideya: user(id: "someid") {
...UserFragment
}
}
答案 0 :(得分:0)
我终于解决了这个问题。试图了解问题的根源,因此我使用新的NetworkLayer来启用适当的日志记录和有意义的错误消息。然后当我的突变失败时抛出一个错误。错误消息为:“无法查询字段clientMutationId ”。看了一下,发现能够改变你需要在GraphQL类型上拥有该字段的对象。所以我加了它。
经验教训:强烈建议您使用 react-relay-network-layer 。
更多详情:
这是我的代码:
import {
RelayNetworkLayer,
urlMiddleware,
batchMiddleware,
} from 'react-relay-network-layer';
Relay.injectNetworkLayer(new RelayNetworkLayer([
batchMiddleware({
batchUrl: 'http://localhost:3000/graphql',
}),
urlMiddleware({
url: 'http://localhost:3000/graphql',
}),
]));
注意:这会启用日志记录,默认情况下它是一个简单的console.log。
以下是我抛出错误的方法:
const params = {
email: email.toLowerCase(),
businessDisplayName: business,
business: business.toLowerCase()
}
var onSuccess = () => {
console.log('Mutation successful!')
}
var onFailure = transaction => {
var error = transaction.getError() || new Error('Mutation failed.')
console.error(error)
}
Relay.Store.commitUpdate(new FindOrCreateUser({ user: { ...params } }), { onFailure, onSuccess })
当然,您总是需要清理缓存并重新启动打包程序。