正则表达式 - 删除模式之间的线条，只保留第一次出现

Question

我需要一个REGEX来删除给定模式的2行之间的行，只保留第一次出现的下一行。像uniq

这样的东西

输入：

Pattern.SomeText
RepeatedLine
RepeatedLine
RepeatedLine
Line

Pattern.OtherText
RepeatedLine

Pattern.ThirdText
RepeatedLine
TTTTRepeatedLine

输出：

Pattern.SomeText
RepeatedLine
Line

Pattern.OtherText 
RepeatedLine

Pattern.Third
TextRepeatedLine
TTTT

带有图案的线条始终以它开头，整条线条是唯一的。我想用Notepad ++制作它。

Answer 1

这是一个正则表达式的例子，它能够找到连续的重复行：

＆＃13;

＆＃13;

const regex = /\n(.+)\n\1\n/g;
const str = `Pattern.SomeText
RepeatedLine
RepeatedLine
RepeatedLine
Line

Pattern.OtherText
RepeatedLine

Pattern.ThirdText
RepeatedLine
TTTT
RepeatedLine`;
const subst = `\n`;

// The substituted value will be contained in the result variable
const result = str.replace(regex, subst);

console.log('Substitution result:\n', result);

＆＃13;

＆＃13;

＆＃13;

如果没有连续的重复行，它将失败。

一个简单的c＃的例子，它完全符合要求：

string pattern = "Pattern.";
string result = "";
string input = @"Pattern.SomeText
RepeatedLine
RepeatedLine
RepeatedLine
Line

Pattern.OtherText
RepeatedLine

Pattern.ThirdText
RepeatedLine
TTTT
RepeatedLine";

var a = input.Split(new string[] { pattern }, StringSplitOptions.None);
foreach (var block in a)
{
    HashSet<string> lastLines = new HashSet<string>(
        block.Split(new string[] { Environment.NewLine }, StringSplitOptions.RemoveEmptyEntries));
    if (lastLines.Any())
    {
        result += pattern + string.Join(Environment.NewLine, lastLines)+Environment.NewLine;
    }
}