访问孩子的WEXITSTATUS

Question

我正在尝试在xCode中访问子项的退出状态，但我不断获得0。但是代码在终端内部运行。我错过了什么吗？

#include <stdio.h>
#include <sys/types.h>
#include <unistd.h>
#include <stdlib.h>
#include <string.h>

int main(int argc, const char * argv[]) {
    int pid, val1;
    char string[11];
    switch ((pid = fork())) {
        case -1:
            printf("An error occured.");
            break;
        case 0:
            printf("Enter max 10 characters: ");
            scanf("%10[^\n]%*c", string);
            exit((int)strlen(string));
        default:
            wait(&val1);
            printf("Child %d died. Count = %d\n", pid, WEXITSTATUS(val1));
            break;
    }
    return EXIT_SUCCESS;
}

xCode的控制台结果：

Enter max 10 characters: Hello
Child 19493 died. Count = 0
Program ended with exit code: 0

在终端内：

Enter max 10 characters: Hello
Child 19504 died. Count = 5