Question

我有3张名为类别，季节和电影的表格。

类别表

+----+---------+------------+-------------+
| id |   name  |    slug    | created_at  |
+----+---------+------------+-------------+
|  1 |    It   |  it-2017   |  SOME TIME  |
|  2 | Another |  another   |  SOME TIME  |
|  3 |SpiderMan| spider-man |  SOME TIME  |
|  4 |  Cars 3 |   cars-3   |  SOME TIME  |
+----+---------+------------+-------------+

四季表

+----+---------+------------+-------------+
| id |  number |category_id | created_at  |
+----+---------+------------+-------------+
|  1 |    1    |     2      |  SOME TIME  |
|  2 |    2    |     2      |  SOME TIME  |
|  3 |    1    |     3      |  SOME TIME  |
|  4 |    3    |     1      |  SOME TIME  |
+----+---------+------------+-------------+

电影表

+----+---------+------------+-------------+
| id |   name  |    slug    |  season_id  |
+----+---------+------------+-------------+
|  1 |  Pilot  |   pilot    |      1      |
|  2 |  Second |   second   |      1      |
|  3 |  Third  |   third    |      1      |
|  4 |  Fourth |   fourth   |      1      |
+----+---------+------------+-------------+

我说这个网址会是这样的

mywebpage.com/serie/ {category_slug} / {来临吧} season_number

但是，在我转到此网址时，查询将显示所有季节中的所有电影。不是当前类别的季节。

我的控制器

public function getMovies($category_slug, $season_number)
{
  $categories = Category::where('slug', $category_slug)->get();
  $seasons = Season::with('movies')->where('number', $season_number)->get();

  return view('routes.getMovies', compact('categories', 'seasons'));
}

我的观点 getMovies.blade.php

@foreach($categories as $category)
    @foreach ($seasons as $season)
      @foreach ($season->movies as $movie)
        Season - {{ $season->number }}
        {{ $movie->name }}
        {{ $movie->description }}
      @endforeach
    @endforeach
@endforeach

我的输出就像所有类别的第1季一样，但我只希望显示当前类别的季节。

Answer 1

首先，确保在模型上设置正确的关系

电影模特

public function season()
{
    return $this->belongsTo(Season::class, 'season_id');
}

季节模型

public function category()
{
    return $this->belongsTo(Category::class, 'category_id');
}

然后，以下将获得具有特定季节编号和特定类别slug的所有电影

$movies = Movie::whereHas('season', function ($season) use ($season_number) {
    $season->where('number', $season_number);
})
->whereHas('season.category', function ($category) use ($category_slug) {
    $category->where('slug', $category_slug);
})
->with('season')
->get();

并在视野中

@foreach ($movies as $movie)
    Season - {{ $movie->season->number }}
    {{ $movie->name }}
    {{ $movie->description }}
@endforeach

Answer 2

试试这个：

$categories = Category::where('slug', $category_slug)->first()->id;

$seasons = Season::with('movies')->where('number', $season_number)->where('category_id', $categories)->get();

查询列在另一个表中的位置 - laravel

2 个答案: