Question

我需要使用圆括号之间的javascript选择一个文本，并将其全部包含在一个范围内：

<p>Just some text (with some text between brackets) and some more text</p>

应该成为：

<p>Just some text <span class="some-class">(with some text between brackets)</span> and some more text</p>

我认为使用正则表达式应该可以做到这一点，但我完全不熟悉在javascript中使用正则表达式。有人可以帮忙吗？谢谢！

Answer 1

这应该可以解决问题（str是包含您想要操作的文本的字符串）：

str.replace((\([^()<>]*\)), "<span class=\"some-class\">$1</span>");

它不允许括号内的(，)，<或>。这样可以避免嵌套问题和html标记落在括号中间。您可能需要对其进行调整以满足您的确切要求。

由于您不熟悉正则表达式，如果您想了解更多信息，我建议您阅读http://www.regular-expressions.info/。

Answer 2

oldString = '<p>Just some text (with some text between brackets) and some more text</p>';
newString = oldString.replace(/\((.*?)\)/g, '<span class="some-class">($1)</span>');

Answer 3

试试这个：

<p id="para">Just some text (with some text between brackets) and some more text</p>
<input type="button" value="Change Text" onclick="ChangeText()"/>
<script>
    function ChangeText()
    {
        var para  = document.getElementById("para");
        var text = para.innerHTML;
        para.innerHTML = text.replace(/(.*)(\(.*\))(.*)/g, "$1<span class=\"some-class\">$2</span>$3")
    }
</script>

Answer 4

使用RegExp对象：

var str = "<p>Just some text (with some text between brackets) and some more text</p>";
var re = new RegExp("\(+(.*)\)+", "g");
var myArray = str.replace(re,"<span class="some-class">($1)</span>" );

使用文字：

var myArray = str.replace(/\(+(.*)\)+/g,"<span class="some-class">($1)</span>")

在javascript中选择圆括号之间的文本

4 个答案: