在Linux中,我正在阅读" / proc / stat"作为btime,我想用c ++ boost转换为可读的日期和时间格式。
我已尝试过以下内容,日期工作正常。
time_t btime_ = 1505790902; //This is epoch time read from "/proc/stat" file.
std::wstring currentDate_ = L"";
boost::gregorian::date current_date_ =
boost::posix_time::from_time_t(btime_).date();
std::wstring year_ = boost::lexical_cast<std::wstring>
(current_date_.year());
std::wstring day_ = boost::lexical_cast<std::wstring>
(current_date_.day());
在这里,我每年都在变得正确。但我如何从上世纪时间获得时间(HH :: MM:SS)?让我说一下 - 我可以试试。
先谢谢。
答案 0 :(得分:2)
只需:
<强> Live On Coliru 强>
System.loadLibrary
打印
#include <ctime>
#include <boost/date_time/posix_time/posix_time_io.hpp>
int main() {
std::time_t btime_ = 1505790902; //This is epoch time read from "/proc/stat" file.
std::cout << boost::posix_time::from_time_t(btime_) << "\n";
std::cout.imbue(std::locale(std::cout.getloc(), new boost::posix_time::time_facet("%H:%M:%S")));
std::cout << boost::posix_time::from_time_t(btime_) << "\n";
}
评论:
<强> Live On Coliru 强>
2017-Sep-19 03:15:02
03:15:02
打印
#include <boost/date_time/posix_time/posix_time_io.hpp>
#include <boost/date_time/c_local_time_adjustor.hpp>
namespace pt = boost::posix_time;
namespace g = boost::gregorian;
using local_adj = boost::date_time::c_local_adjustor<pt::ptime>;
int main() {
std::cout.imbue(std::locale(std::cout.getloc(), new pt::time_facet("%H:%M:%S")));
std::time_t btime_ = 1505790902; // This is epoch time read from "/proc/stat" file.
pt::ptime const timestamp = pt::from_time_t(btime_);
std::cout << timestamp << "\n";
// This local adjustor depends on the machine TZ settings
std::cout << local_adj::utc_to_local(timestamp) << " local time\n";
}
答案 1 :(得分:1)
您可以使用time_facet
。这是打印UTC日期/时间的示例:
std::string PrintDateTime()
{
std::stringstream str;
boost::posix_time::time_facet *facet = new boost::posix_time::time_facet("%d.%m.%Y-%H:%M:%S-UTC");
str.imbue(std::locale(str.getloc(), facet));
str << boost::posix_time::second_clock::universal_time(); //your time point goes here
return str.str();
}
请注意,您无需担心facet
的内存管理问题。它已经从内部得到了照顾。