Question

为什么symfony忽略我的自定义规范化器？

的src /的appbundle /串行器/正规化/ ExceptionNormalizer.php

<?php

namespace AppBundle\Serializer\Normalizer;

use Symfony\Component\Serializer\Normalizer\NormalizerInterface;

/**
 * Class ExceptionNormalizer
 */
class ExceptionNormalizer implements NormalizerInterface
{
    /**
     * {@inheritdoc}
     */
    public function normalize($object, $format = null, array $context = array()): array
    {
        return [];
    }

    /**
     * {@inheritdoc}
     */
    public function supportsNormalization($data, $format = null): bool
    {
        return $data instanceof \Exception;
    }
}

的src /的appbundle /资源/配置/ services.yml

services:
    ...
    app.normalizer.exception:
        class: AppBundle\Serializer\Normalizer\ExceptionNormalizer
        tags:
            - { name: serializer.normalizer }

应用/配置/ config.yml

imports:
    - { resource: parameters.yml }
    - { resource: security.yml }
    #- { resource: services.yml } exclude default services file
    - { resource: "@AppBundle/Resources/config/services.yml" }

异常输出

{＆＃34;错误＆＃34;：{＆＃34;代码＆＃34;：404，＆＃34;消息＆＃34;：＆＃34;未找到＆＃34;，＆＃34;异常＆＃ 34;：[{＆＃34; message＆＃34;：＆＃34; AppBundle \ Entity \ User object not found。＆＃34;，＆＃34; class＆＃34;：＆＃34; Symfony \ Component .. ...

预期的异常输出

{}

Answer 1

你不应该规范异常。相反，为这种异常创建侦听器，处理它（例如，写入日志）并将所需的输出作为Response返回。

class ExceptionListener
{
/** @var LoggerInterface */
private $logger;


public function __construct(LoggerInterface $logger)
{
    $this->logger = $logger;
}

public function onKernelException(GetResponseForExceptionEvent $event)
{
    $e = $event->getException();
    if ($e instanceof ValidationException) {
        $event->setResponse(new JsonResponse(['error' => $e->getViolations()], 422)
    } elseif ($e instanceof DomainException) {
        $this->logger->warning('Exception ' . get_class($e) , ['message' => $e->getMessage()]);
        $event->setResponse(
        new JsonResponse(['error' => 'Something is wrong with your request.'], 400);
    } elseif ($e instanceof NotFoundHttpException) {
        $event->setResponse(new JsonResponse(['error' => 'Not found.'], 404);
    } else {
        $event->setResponse(new JsonResponse(['error' => $this->translator->trans('http.internal_server_error')], 500);
    }
}

}

更新services.yml

  app.exception_listener:
    class: Application\Listeners\ExceptionListener
    arguments: ['@domain.logger']
    tags:
      - { name: kernel.event_listener, event: kernel.exception }

进一步阅读有关听众和活动的信息https://symfony.com/doc/current/event_dispatcher.html

您的规范化器很可能被忽略，因为您没有在序列化程序中注册它。

Symfony 3.3.8忽略自定义规范化程序

1 个答案: