在from math import cos, pi, sin
from random import random
from matplotlib.mlab import frange
from matplotlib.pyplot import plot, axis, show,axes
LEN = 0.1
def rotate(point, theta):
x = point[0]
y = point[1]
x_ = x * cos(theta) + y * sin(theta)
y_ = - x * sin(theta) + y * cos(theta)
return x_, y_
class CUBE(object):
def __init__(self, x, y, theta):
self.corner = [(LEN / 2, LEN / 2),
(-LEN / 2, LEN / 2),
(-LEN / 2, -LEN / 2),
(LEN / 2, -LEN / 2)
]
self.theta = theta
self.x = x
self.y = y
for i in range(4):
self.corner[i] = rotate(self.corner[i], theta)
self.corner[i] = (self.corner[i][0] + x,
self.corner[i][1] + y)
def is_include(cube, point):
point = [point[0] - cube.x, point[1] - cube.y]
point = rotate(point, -cube.theta)
if (point[0] < -LEN / 2
or point[0] > LEN / 2
or point[1] < -LEN / 2
or point[1] > LEN / 2
):
return False
else:
return True
def is_intersect(cube1, cube2):
if (any([is_include(cube1, point) for point in cube2.corner])
or any([is_include(cube2, point) for point in cube1.corner])
or is_include(cube1, (cube2.x, cube2.y))):
return True
else:
return False
def plot_cube(cube,n):
plot(
[cube.corner[i][0] for i in [0, 1, 2, 3, 0]],
[cube.corner[i][1] for i in [0, 1, 2, 3, 0]])
ax = axes()
ax.text(cube.x,cube.y,str(n))
def display(cubelist): # connects the 4 corners on a plot
for i,cube in enumerate(cubelist):
plot_cube(cube,i)
axis([0, 1, 0, 1]) # 1x1 grid
show()
cubelist = []
for i in range(100):
x0 = random()
y0 = random()
theta = random() * pi
cube = CUBE(x0, y0, theta)
if any(is_intersect(cube,cb) for cb in cubelist):
continue
else:
cubelist.append(cube)
display(cubelist)
控件中，当我想要更改ListView时，如何使用DisplayMemberPath属性？
我在我的控件的ItemContainerStyle中使用了ListView控件，ControlTemplate属性是通过DisplayMemberPath从控件之外设置的。
Binding是否可以在 XAML 中解决此问题？它是如何在原<ListView ItemsSource="{TemplateBinding ItemsSource}"
DisplayMemberPath="{TemplateBinding DisplayMemberPath}">
<ListView.ItemsPanel>
<ItemsPanelTemplate>
<StackPanel Orientation="Horizontal" />
</ItemsPanelTemplate>
</ListView.ItemsPanel>
<ListView.ItemContainerStyle>
<Style TargetType="{x:Type ListViewItem}">
<Setter Property="Template">
<Setter.Value>
<ControlTemplate TargetType="{x:Type ListViewItem}">
<StackPanel Orientation="Horizontal">
<TextBlock Text="Item:" />
<TextBlock Text="{Binding}" />
<TextBlock Text=", " />
</StackPanel>
</ControlTemplate>
</Setter.Value>
</Setter>
</Style>
</ListView.ItemContainerStyle>
</ListView>
中解决的？
我尝试用ControlTemplate来解决它，我绑定了Collection Item和MultiValueConverter。
DisplayMemberPath有必要吗？或者它是原始<TextBlock>
<TextBlock.Text>
<MultiBinding Converter="{StaticResource NameToValueConverter}">
<Binding />
<Binding Path="DisplayMemberPath" RelativeSource="{RelativeSource FindAncestor, AncestorType={x:Type ListView}}"/>
</MultiBinding>
</TextBlock.Text>
</TextBlock>
控件已解决的显示值？
答案 0 :(得分：2)
是否有可能通过XAML解决？
不，您使用 <script src="https://cdnjs.cloudflare.com/ajax/libs/d3/3.4.11/d3.min.js"></script>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<svg viewbox="0 0 1600 1600" width="500" height="500">
<g id ='aa' onclick="rotate()">
<rect x="100", y="100" width="100" height="100" />
<circle cx="250" cy="150" r="50"/>
</g>
<g class ='aa' onclick="rotate2()">
<rect x="600", y="100" width="100" height="100" />
<circle cx="750" cy="150" r="50" />
</g>
</svg>或DisplayMemberPath / ItemTemplate，但不能同时使用两者。
此外，ItemContainerStyle属性应设置为DisplayMemberPath，指定基础数据类的属性名称。 不是一个可以绑定的依赖项属性。