Question

我有两个日期字段campaign_start_date和campaign_end_date。我想计算campaign_start_date和campaign_end_date之间每个月的天数。

例如：

campaign_start_date  = September 7 2017
campaign_end_date    = November 6 2017

解决方案应该是：

Total No:of days       = 61 days
No: of months          = 3 months
Month 1                = 9/7/2017 to 9/30/2017
Month 2                = 10/1/2017 to 10/31/2017
Month 3                = 11/1/2017 to 11/6/2017
No:of days in Month 1  = 24 days
No:of days in Month 2  = 31 days
No:of days in Month 3  = 6 days

如何使用Python实现这一目标？到目前为止，我已经实现了：

@api.multi
    def print_date(self):
        start_date = datetime.strptime(self.start_date, "%Y-%m-%d %H:%M:%S")
        end_date = datetime.strptime(self.end_date, "%Y-%m-%d %H:%M:%S")
        campaign_start_date = date(start_date.year,start_date.month,start_date.day)
        campaign_end_date = date(end_date.year,end_date.month,end_date.day)
        duration = (campaign_end_date-campaign_start_date).days  
        return True

Answer 1

以天计算持续时间：

from datetime import date

campaign_start_date = date(2017, 9, 7)
campaign_end_date = date(2017, 10, 6)
duration = (campaign_end_date-campaign_start_date).days
print campaign_start_date, campaign_end_date, duration

进一步计算的一些提示：

import calendar

campaign_end_month_start = campaign_end_date.replace(day=1)
days_in_month_campaign_end = (campaign_end_date - campaign_end_month_start).days + 1

range_startmonth = calendar.monthrange(campaign_start_date.year, campaign_start_date.month)
campaign_start_month_ends = campaign_start_date.replace(day=range_startmonth[1])

days_in_month_campaign_begins = (campaign_start_month_ends - campaign_start_date).days

通过这种方式，您可以计算广告系列每个月的天数（请注意检查campaign_end_date是否在另一个月内campaign_start_date

对于计算，您还可以访问日期的字段，例如

campaign_start_date.day
campaign_start_date.month
campaign_start_date.year

要计算广告系列中涉及的月份数量，并获取月份列表以计算每月的持续时间，您可以使用此值（根据Python: get all months in range?中m.antkowicz的答案）。在循环之前和之内将日期设置为1（current = current.replace(day=1)）非常重要，否则您跳过一个月，当您的开始日期是一个月31日，下个月短于31天或者如果您有更长的时间：

from datetime import date, datetime, timedelta    
current = campaign_start_date
result = [current]

current = current.replace(day=1)
while current <= campaign_end_date:
    current += timedelta(days=32)
    current = current.replace(day=1)
    result.append(datetime(current.year, current.month, 1))

print result, len(result)

打印（当您使用current.strftime('%Y-%m-%d')时：

['2017-09-07'，'2017-10-01'，'2017-11-01'] 3

现在您可以遍历结果列表并计算每月的天数：

durations= []
for curr in result:
    curr_range = calendar.monthrange(curr.year, curr.month)
    curr_duration = (curr_range[1] - curr.day)+1
    if (curr.month < campaign_end_date.month):
        durations.append(curr_duration)
    else:
        durations.append(campaign_end_date.day)

print durations

为您提供所需的“No：of Month in Month x”作为列表：

[24,31,6]

Answer 2

这是一种强大的解决方案，可以处理不同年份的日期。

def get_months_and_durations(start_date,end_date):
    current = start_date
    result = [current]

    current = current.replace(day=1)
    while current <= end_date:
        current += timedelta(days=32)
        current = current.replace(day=1)
        result.append(datetime(current.year, current.month, 1).date())

    durations= []
    for curr in result[:-1]:
        curr_range = calendar.monthrange(curr.year, curr.month)
        curr_duration = (curr_range[1] - curr.day)+1

        if ((curr.month == end_date.month) & (curr.year == end_date.year)):
            durations.append(end_date.day)
        else:
            durations.append(curr_duration)
    return result[:-1],durations

如何获取Python中两个日期之间特定月份的天数

2 个答案: