Question

当我运行该程序时，即使我已经输入一次，它也会多次询问我的输入。

Peeps = {"Juan":244, "Jayne":433, "Susan":751}

要求用户输入一个名称，该名称是值的关键，并返回

for i in Peeps:
    if i == input("Type in a name: "):
        print("The amount", [i], "owes is:", "$" + str(Peeps[i]))
        break
    else:
        print("Sorry that name does not exist, please enter a new name.")

Answer 1

您需要先询问用户输入，而不是直接将用户输入与密钥进行比较。

Answer 2

你不想这样做。请看一下以下内容：

Peeps = {"Juan":244, "Jayne":433, "Susan":751}
name = input("Type in a name: ")
if name in Peeps:
    print("The amount", name, "owes is:", "$" + str(Peeps[name]))
else:
    print("Sorry that name does not exist, please enter a new name.")

您不必遍历dict并单独检查每个值的用户输入（另外，您强制用户更新\连续输入他的输入）。

只需接收一次即可处理。

如果您想保持循环运行以允许多个查询，请使用while，如下所示：

Peeps = {"Juan": 244, "Jayne": 433, "Susan": 751}
name = input("Type in a name or leave blank to exit: ")
while name:
    if name in Peeps:
        print("The amount", name, "owes is:", "$" + str(Peeps[name]))
    else:
        print("Sorry that name does not exist, please enter a new name.")
    name = input("Type in a name or leave blank to exit: ")

当我运行程序时，即使我已经输入一次，它也会多次询问我的输入

2 个答案: