Question

我有两个打开的MainWindows：MainWindowWithButton和MainWindowWithDock。后者包含一个QDockWidget。

IS行为：当用户使DockWidget浮动并关闭MainWindowWithDock时，dockWidget不会关闭。

SHOULD行为：当用户使DockWidget浮动并关闭MainWindowWithDock时，dockWidget也会关闭。

注意：

＆＃34; IS行为的原因＆＃34;：浮动的DockWidget似乎独立于它的父母
我无法听取onClose / reject（因为它会在我的特定情况下提供虚假信息。
MainWindow没有发出有关其行为的明确信号
重要的是，DockWidget在关闭MainWindow之前关闭 。否则焦点会出乎意料

示例代码：

from PyQt4 import QtCore, QtGui from PyQt4 import QtCore, QtGui from PyQt4.QtGui import QApplication, QDialog, QMainWindow import sys try: _fromUtf8 = QtCore.QString.fromUtf8 except AttributeError: def _fromUtf8(s): return s try: _encoding = QtGui.QApplication.UnicodeUTF8 def _translate(context, text, disambig): return QtGui.QApplication.translate(context, text, disambig, _encoding) except AttributeError: def _translate(context, text, disambig): return QtGui.QApplication.translate(context, text, disambig) class Ui_MainWindowWithButton(object): def setupUi(self, MainWindowWithButton): MainWindowWithButton.setObjectName(_fromUtf8("MainWindowWithButton")) MainWindowWithButton.resize(567, 384) self.centralwidget = QtGui.QWidget(MainWindowWithButton) self.centralwidget.setObjectName(_fromUtf8("centralwidget")) MainWindowWithButton.setCentralWidget(self.centralwidget) def retranslateUi(self, MainWindowWithButton): MainWindowWithButton.setWindowTitle(_translate("MainWindowWithButton", "MainWindow", None)) class Ui_MainWindowWithDock(object): def setupUi(self, MainWindowWithDock): MainWindowWithDock.setObjectName(_fromUtf8("MainWindowWithDock")) MainWindowWithDock.resize(509, 316) self.centralwidget = QtGui.QWidget(MainWindowWithDock) self.centralwidget.setObjectName(_fromUtf8("centralwidget")) MainWindowWithDock.setCentralWidget(self.centralwidget) # # # # # # # # # # # # # # # # # # # # # # # # # setup dock # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # self.theDock = QtGui.QDockWidget(MainWindowWithDock) self.theDock.setObjectName(_fromUtf8("theDock")) self.dockWidgetContents = QtGui.QWidget(self.theDock) self.dockWidgetContents.setObjectName(_fromUtf8("dockWidgetContents")) self.theDock.setWidget(self.dockWidgetContents) MainWindowWithDock.addDockWidget(QtCore.Qt.DockWidgetArea(2), self.theDock) self.retranslateUi(MainWindowWithDock) QtCore.QMetaObject.connectSlotsByName(MainWindowWithDock) def retranslateUi(self, MainWindowWithDock): MainWindowWithDock.setWindowTitle(_translate("MainWindowWithDock", "MainWindow", None)) class MainWindowWithButtonDlg(QMainWindow): pass class MainWindowWithDockDlg(QMainWindow): pass def main(): app = QApplication(sys.argv) windowWithDockUi = Ui_MainWindowWithDock() windowWithDock = MainWindowWithDockDlg() windowWithDockUi.setupUi(windowWithDock) windowWithDock.show() app.exec() # the dock widget should be closed by now ui = Ui_MainWindowWithButton() window = MainWindowWithButtonDlg() ui.setupUi(window) window.show() app.exec() if __name__ == '__main__': main()

拒绝原始来源的方法。在这里，我们有一个带有QMainwindow的QDialog作为它的中央Widget - 因此它在某种意义上变成了QMainWindow（from Anki addCards.py (scroll to bottom)：

def reject(self): if not self.canClose(): # this way of calling is basically the problem: we might leave this method without doing anything return remHook('reset', self.onReset) remHook('currentModelChanged', self.onModelChange) clearAudioQueue() self.removeTempNote(self.editor.note) self.editor.setNote(None) self.modelChooser.cleanup() self.deckChooser.cleanup() self.mw.maybeReset() saveGeom(self, "add") aqt.dialogs.close("AddCards") QDialog.reject(self)

Answer 1

您可以使用event-filter来监控给定窗口的所有事件。在窗口关闭之前，它将始终发布一个关闭事件。窗口是否修改了正常的关闭过程并不重要。如果它最终关闭，则相应的关闭事件的accept property 保证为True。因此，如果您观看此活动，您只需检查是否已被接受，然后采取相应行动。

要解决的主要问题是如何找到合适的观看窗口。在创建dock-widget时，可能无法访问它。因此，一种方法是等待直到第一次显示dock-widget的父级，然后查找顶级窗口并在其上安装事件过滤器。以这种方式做事意味着dock-widget永远不需要了解它最终依赖的窗口。

以下是基于您的示例的此方法的工作演示（删除了大部分不相关的内容）：

import sys
from PyQt4 import QtCore, QtGui
from PyQt4.QtGui import QApplication, QDialog, QMainWindow

class EventWatcher(QtCore.QObject):
    def __init__(self, parent):
        QtCore.QObject.__init__(self, parent)
        parent.installEventFilter(self)

    def eventFilter(self, source, event):
        if source is self.parent():
            if event.type() == QtCore.QEvent.Show:
                target = source.parent()
                while target.parent() is not None:
                    target = target.parent()
                print('found target window: %r' % target)
                source.removeEventFilter(self)
                target.installEventFilter(self)
        elif event.type() == QtCore.QEvent.Close:
            source.closeEvent(event)
            print('test filter accepted: %s' % event.isAccepted())
            if event.isAccepted():
                self.parent().close()
            return True
        return QtCore.QObject.eventFilter(self, source, event)

class Ui_MainWindowWithDock(object):
    def setupUi(self, MainWindowWithDock):
        self.theDock = QtGui.QDockWidget(MainWindowWithDock)
        MainWindowWithDock.addDockWidget(QtCore.Qt.DockWidgetArea(2), self.theDock)
        # add the event watcher
        EventWatcher(self.theDock)

class MainWindowWithDockDlg(QMainWindow):
    pass

# mock-up class for testing
class MockDialog(QDialog):
    def __init__(self):
        QDialog.__init__(self)
        windowWithDock = MainWindowWithDockDlg()
        windowWithDockUi = Ui_MainWindowWithDock()
        windowWithDockUi.setupUi(windowWithDock)
        layout = QtGui.QVBoxLayout(self)
        layout.addWidget(windowWithDock)
        self.canClose = False

    def reject(self):
        if not self.canClose:
            self.canClose = True
            return
        QDialog.reject(self)

    def closeEvent(self, event):
        QDialog.closeEvent(self, event)
        print('test close accepted: %s' % event.isAccepted())

def main():
    app = QApplication(sys.argv)

    dialog = MockDialog()
    dialog.show()
    app.exec_()

    # the dock widget should be closed by now

    window = QMainWindow()
    window.show()
    app.exec_()

if __name__ == '__main__':
    main()

当parentWidget关闭时，浮动QDockWidget不会关闭

1 个答案: