Question

我正在使用python 2.6.6

我只是想从一开始就根据用户输入重启程序。感谢

import random
import time
print "You may press q to quit at any time"
print "You have an amount chances"
guess = 5
while True:
    chance = random.choice(['heads','tails'])
    person = raw_input(" heads or tails: ")
    print "*You have fliped the coin"
    time.sleep(1)
    if person == 'q':
         print " Nooo!"
    if person == 'q':
        break   
    if person == chance:
        print "correct"
    elif person != chance:
        print "Incorrect"
        guess -=1
    if guess == 0:
        a = raw_input(" Play again? ")
        if a == 'n':
            break
        if a == 'y':
            continue

#Figure out how to restart program

我对continue语句感到困惑。因为如果我继续使用，我在第一次输入“y”后就永远不会选择“再次播放”。

Answer 1

在您希望重新启动循环的位置使用continue语句。就像您使用break来断开循环一样，continue语句将重新启动循环。

不是基于您的问题，而是如何使用continue：

while True: 
        choice = raw_input('What do you want? ')
        if choice == 'restart':
                continue
        else:
                break

print 'Break!'

此外：

choice = 'restart';

while choice == 'restart': 
        choice = raw_input('What do you want? ')

print 'Break!'

输出：

What do you want? restart
What do you want? break
Break!

Answer 2

我建议：

将您的代码分解为函数;它使它更具可读性
使用有用的变量名称
不消耗你的常量（第一次通过你的代码后，你怎么知道开始有多少猜测？）

import random
import time

GUESSES = 5

def playGame():
    remaining = GUESSES
    correct = 0

    while remaining>0:
        hiddenValue = random.choice(('heads','tails'))
        person = raw_input('Heads or Tails?').lower()

        if person in ('q','quit','e','exit','bye'):
            print('Quitter!')
            break
        elif hiddenValue=='heads' and person in ('h','head','heads'):
            print('Correct!')
            correct += 1
        elif hiddenValue=='tails' and person in ('t','tail','tails'):
            print('Correct!')
            correct += 1
        else:
            print('Nope, sorry...')
            remaining -= 1

    print('You got {0} correct (out of {1})\n'.format(correct, correct+GUESSES-remaining))

def main():
    print("You may press q to quit at any time")
    print("You have {0} chances".format(GUESSES))

    while True:
        playGame()
        again = raw_input('Play again? (Y/n)').lower()
        if again in ('n','no','q','quit','e','exit','bye'):
            break

Answer 3

您需要使用random.seed初始化随机数生成器。如果每次都使用相同的值调用它，则random.choice中的值将重复。

Answer 4

输入'y'后，guess == 0永远不会为真。

如何重新开始简单的投币游戏

4 个答案: