Question

我在一个formview中有一个面板，当我选中一个复选框（也在formview中）时，该面板应该可见。我能够访问控件，但我不知道如何实际使它工作。到目前为止，这是我的代码隐藏，我知道它不对，但它给出了我正在尝试做的基本概念。

Protected Sub FormView1_DataBound(ByVal sender As Object, ByVal e As System.EventArgs) Handles FormView1.DataBound
    If FormView1.CurrentMode = FormViewMode.Edit Then

        Dim checkGenEd As CheckBox = FormView1.FindControl("checkGenEd")
        Dim panelOutcome As Panel = FormView1.FindControl("panelOutcome")

        If checkGenEd.Checked = True Then
            panelOutcome.Visible = True
        Else
            panelOutcome.Visible = False
        End If

    End If
End Sub

Answer 1

问题有点不清楚，但如果你想要选中/取消选中复选框，那么你需要使用复选框的OnCheckChanged事件：

    <asp:TemplateField>
    <ItemTemplate>
        <asp:CheckBox ID="checkGenEd" AutoPostBack="true" Checked='<%# Eval("YourDBField") %>' OnCheckedChanged="checkGenEd_CheckedChanged" runat="server" />            
    </ItemTemplate>
    </asp:TemplateField> 

    Protected Sub checkGenEd_CheckedChanged(ByVal sender As Object, ByVal e As System.EventArgs)
            Dim checkGenEd As CheckBox = DirectCast(sender, CheckBox)
            Dim panelOutcome As Panel = FormView1.FindControl("panelOutcome")

            If checkGenEd.Checked = True Then
                panelOutcome.Visible = True
            Else
                panelOutcome.Visible = False
           End If
End Sub

ASP.NET / VB：改变formview中面板的可见性

1 个答案: