用c＃创建新的sql server表

Question

我有这个代码来创建新的sql表 当我执行它时它显示我在屏幕截图上的这个错误。在我的数据库中没有这样的表。它显示此错误的任何名称的表。有谁可以帮助我？

public void Create(string TName, string ConString)
    {
        try
        {
            using (SqlCommand cmd = new SqlCommand("CREATE TABLE [dbo].['" + TName + "']("
                            + "[ID] [int] IDENTITY(1,1) NOT NULL,"
                            + "[DateTime] [date] NOT NULL,"
                            + "[BarCode] [nvarchar](max) NOT NULL,"
                            + "[ArtNumber] [nvarchar](max) NOT NULL,"
                            + "[ProductName] [nvarchar](50) NOT NULL,"
                            + "[Quantity] [int] NOT NULL,"
                            + "[SelfPrice] [decimal](18, 2) NOT NULL,"
                            + "[Price] [decimal](18, 2) NOT NULL,"
                            + "[Disccount] [int] NULL,"
                            + "[Comment] [nvarchar](max) NULL,"
                            + "CONSTRAINT ['" + TName + "'] PRIMARY KEY CLUSTERED "
                            + "("
                            + "[ID] ASC"
                            + ")WITH (PAD_INDEX  = OFF, STATISTICS_NORECOMPUTE  = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS  = ON, ALLOW_PAGE_LOCKS  = ON) ON [PRIMARY]"
                            + ") ON [PRIMARY]", new SqlConnection(ConString)))
            {
                cmd.Connection.Open();
                cmd.ExecuteNonQuery();
                cmd.Connection.Close();
            }
        }
        catch (Exception)
        {

            throw;
        }
    }

Answer 1

您对表及其主键使用相同的名称。请改为"CONSTRAINT ['pk_" + TName + "'] PRIMARY KEY CLUSTERED "。

Answer 2

错误消息似乎与表的名称无关。它似乎与约束的名称有关。看起来您正在命名一个约束'beso'，并且该名称中的另一个对象已存在于您的数据库中。

Answer 3

您也可以使用Mig#来代替使用SQL语法：

        var schema = new DbSchema(ConnectionString, DbPlatform.SqlServer2014);
        schema.Alter(db => db.CreateTable(TName)
           .WithPrimaryKeyColumn("Id", DbType.Int32).AsIdentity()
           .WithNotNullableColumn("DateTime", DbType.Date)
           ...);

这种方法的唯一缺点是Mig＃不适合使用非常特定于SQL Server的功能，因为它以便携方式支持许多平台。