Question

过去几天我一直试图想出以下几点。

table1：同义词

Id         Synonym       code

------------------------------
1          Car Tyre      001

2          Bike Tyre     002

3          Cycle Tyre    003

4          Hammer Tube   001

现在我的输入=＆＃39;来自Hammer Tube AUDI 2000的汽车轮胎＆＃39;

输出=列表代码＆＃39; 001＆＃39;两次，因为输入文本包含＆＃39; CAR TIRE＆＃39;和＆＃39; Hammer Tube＆＃39;

当我尝试以下查询时，它只显示一次，但我需要两次

Select * from synonym where 'WITH CAR TYRE FROM Hammer Tube AUDI 2000' ~ Synonym;

Answer 1

将position()与lower()结合使用：

with synonym(id, synonym, code) as (
values
    (1, 'Car Tyre', '001'),
    (2, 'Bike Tyre', '002'),
    (3, 'Cycle Tyre', '003'),
    (4, 'Hammer Tube', '001')
)

select *
from synonym
where position(lower(synonym) in lower('WITH CAR TYRE FROM Hammer Tube AUDI 2000')) > 0

 id |   synonym   | code 
----+-------------+------
  1 | Car Tyre    | 001
  4 | Hammer Tube | 001
(2 rows)

Postgres正则表达式子串或regexp_matches

1 个答案: