Question

大家好我需要这个问题的帮助：骰子滚动游戏是用两个六面骰子玩的。玩游戏的用户将掷出两个骰子，并且将生成一到六个之间的两个随机数。这两个数字的总和将用于决定下一步。如果总和是2,3或12，则玩家获胜。如果总和是7或11则他/她输了。如果总和为4,5,6,8,9或10，那么程序会自动再次掷骰子直到玩家获胜或输掉。每次掷骰子后，都会提示玩家输入。玩家应该决定游戏是否应该继续。每次骰子滚动后也应显示赢和输的游戏数量。我已设法让第一部分工作，但无法确定如何提示用户，如果他们希望继续或他们赢了/输了多少游戏

public class DiceGame {

    /**
     * @param args the command line arguments
     */
    public static void main(String[] args) {

        while (true) {
            int dice1=(int)(Math.random()*6+1);
            int dice2=(int)(Math.random()*6+1);
            int sum = dice1 + dice2;

            System.out.println("Roll: total = " + sum);

            if (sum==2 || sum==3 || sum==12) {
                System.out.println("Sorry with a " +  sum  + " you loose :(");
                break;
            }
            else if(sum==7 || sum==11) {
                System.out.println("With a " + sum + " you win :)");
                break;
            }
        }
    }

}

Answer 1

扫描仪可用于提示用户询问他/她是否想要继续。

你甚至可以追踪没有。时间骰子滚动。

import java.util.Scanner;

public class DiceGame {

    public static int attempt = 1;
    /**
     * @param args
     *            the command line arguments
     */
    public static void main(String[] args) {

        Scanner scanner = new Scanner(System.in);
        int dice1 = (int) (Math.random() * 6 + 1);
        int dice2 = (int) (Math.random() * 6 + 1);
        int sum = dice1 + dice2;

        while (true) {
            System.out.println();
            System.out.println("Rolling dice for " + attempt + " time!");

            dice1 = (int) (Math.random() * 6 + 1);
            dice2 = (int) (Math.random() * 6 + 1);
            sum = dice1 + dice2;

            System.out.println("Roll: total = " + sum);

            if (sum == 2 || sum == 3 || sum == 12) {
                System.out.println("Sorry with a " + sum + " you loose :(!");
                System.out.println();
                break;
            } else if (sum == 7 || sum == 11) {
                System.out.println("With a " + sum + " you win :)!");
                System.out.println();
                break;
            }
            System.out.println();
            System.out.println("Do you wish to continue? Press 'y' for YES or ANY key for EXIT");
            if (!scanner.next().equalsIgnoreCase("y")) {
                break;
            }
            attempt++;
        }
        System.out.println("Thanks for playing dice game, you rolled the dice " + attempt + " times!");
    }
}

EDIT:如果您希望在总和为4 5 6 8 9 10时自动滚动骰子，那么您将不再需要扫描仪，即用户输入是否继续。

以下是相同的解决方案。

public class DiceGame {

    public static int attempt = 1;

    public static void main(String[] args) {

        int dice1 = 0;
        int dice2 = 0;
        int sum = 0;

        while (true) {
            System.out.println();
            System.out.println("Rolling dice for " + attempt + " time!");

            dice1 = (int) (Math.random() * 6 + 1);
            dice2 = (int) (Math.random() * 6 + 1);
            sum = dice1 + dice2;

            System.out.println("Roll: total = " + sum);

            if (sum == 2 || sum == 3 || sum == 12) {
                System.out.println("Sorry with a " + sum + " you loose :(!");
                System.out.println();
                break;
            } else if (sum == 7 || sum == 11) {
                System.out.println("With a " + sum + " you win :)!");
                System.out.println();
                break;
                // this will roll the dices automatically
                // when sum is 4, 5, 6, 8, 9 or 10
            } else {
                System.out.println();
                System.out.println("With " + sum + " dices are rolled again automatically!!");
                attempt++;
            }
        }
        System.out.println("Thanks for playing dice game, you rolled the dice " + attempt + " times!");
    }
}

示例运行

Rolling dice for 1 time!
Roll: total = 4

With a 4, dices are rolled again automatically!!

Rolling dice for 2 time!
Roll: total = 6

With a 6, dices are rolled again automatically!!

Rolling dice for 3 time!
Roll: total = 2
Sorry with a 2 you loose :(!

Thanks for playing dice game, you rolled the dice 3 times!

Answer 2

您可以使用java Scanner类来提示用户输入。

在while循环中，提示用户输入。您可能需要修改while循环条件。

Scanner sc = new Scanner(System.in);
int i = sc.nextInt();

根据用户的输入，使用'brake'退出循环。应该这样做。

Scanner Reference

Answer 3

我创建了一个返回int的playAgainMessage方法。这决定用户是否将再次播放。看看：

import java.util.Scanner;

public class DiceGame {
    private static final int PLAY = 1;
    private static final int DO_NOT_PLAY = 2;
    private static int choice = 1;

    public static void main(String[] args) {
        while (choice == PLAY) {
            int dice1=(int)(Math.random()*6+1);
            int dice2=(int)(Math.random()*6+1);
            int sum = dice1 + dice2;

            System.out.println("Roll: total = " + sum);

            if (sum==2 || sum==3 || sum==12) {
                System.out.println("Sorry with a " +  sum  + " you loose :(");
                choice = playAgainMessage();
            }
            else if(sum==7 || sum==11) {
                System.out.println("With a " + sum + " you win :)");
                choice = playAgainMessage();
            }
        }
        if (choice == DO_NOT_PLAY) {
            System.out.println("Good bye...");
        }
    }

    private static int playAgainMessage() {
        Scanner input = new Scanner(System.in);
        System.out.println("Would you like to play again? '1' for yes, '2' for no");
        int choice = input.nextInt();
        input.close();
        if(choice == PLAY){
            System.out.println("Rolling...");
            return PLAY;
        } else {
            return DO_NOT_PLAY;
        }
    }
}

您可以随时调用playAgainMessage方法，这样可以轻松阅读。

这将继续播放，直到用户输入“1”以外的内容。尝试运行它以查看确切的输出。

Answer 4

您可以使用do{}while();循环，它会播放一次，然后再次询问用户：

Scanner sc = new Scanner(System.in);
String input = "";
do {
    int // ...

    System.out.println("Roll: total = " + sum);

    if (sum == 2 || sum == 3 || sum == 12) {
        // ...
    } else if (sum == 7 || sum == 11) {    
        // ...
    }

    System.out.println("If you want to continue, write 'y' : ");
    input = sc.nextLine();
} while (input.equalsIgnoreCase("y"));

如何使用netbeans

4 个答案: