Question

我有一个看起来像这样的结构：

struct colorShapeSize{
    let color: String!
    let shape: String!
    let size: UIImage!
}

我有一个看起来像这样的字符串：

"color:{Blue}shape:{round}size:{medium}"

所有字符串都采用相同的格式（即颜色始终为第一，第二形，第三尺寸）。

如何从字符串中提取数据并将其放入colorShapeSize结构中？

Answer 1

这个怎么样？

struct ColorShapeSize {
    let color: String
    let shape: String
    let size: String

    init(rawValue: String) {
        var dictionary: [String: String] = [:]
        var sorted = rawValue.components(separatedBy: "}").filter({ return $0.components(separatedBy: ":{").count == 2 })
        for s in sorted {
            let kv = s.components(separatedBy: ":{")
            let key = kv[0]
            let value = kv[1]
            dictionary[key] = value
        }

        color = dictionary["color"] ?? ""
        shape = dictionary["shape"] ?? ""
        size = dictionary["size"] ?? ""
    }
}

let str = "color:{Blue}shape:{round}size:{medium}"
let css = ColorShapeSize(rawValue: str)
print(css.color, css.shape, css.size)

Answer 2

试试这个，它会在数组中提取字符串，然后你可以用值

做你想做的事

func test() {
    let givenString = "color:{Blue}shape:{round}size:{medium}"
    var results = [String]()
    do {
        let regex = try NSRegularExpression(pattern: "\\{(.*?)\\}", options: [])
        let tempString = givenString as NSString
        regex.enumerateMatches(in: givenString, options: [], range: NSMakeRange(0, givenString.characters.count), using: { (result, flag, stop) in
            if let range = result?.rangeAt(1) {
                let number = tempString.substring(with: range)
                results.append(number)
            }
        })
        print(results) //["Blue", "round", "medium"] (Here you can initialize your struct with the values)
    }
    catch(let error) {
        print("Unable to extract string : \(error.localizedDescription)")
    }
}

Swift中的字符串解释

2 个答案: