出于某些原因,在django中,我尝试使用的表单不被视为有效。此代码几乎直接来自声称其有效但仍无法正常运行的网站。 我的代码如下。
视图
def display_update_image(request, pk):
if request.method == 'POST':
form = ImageForm(request.POST, request.FILES)
if form.is_valid():
display = Display.objects.get(pk = pk)
display.image = form.cleaned_data['image']
display.save()
return HttpResponseRedirect(reverse('displays'))
else :
form = ImageForm()
return render(request, 'catalog/update_display_image.html', {'form': form})
TEMPLATE(模板名称为update_display_image.html)
<form method = "post" enctype = "multipart/form-data">{% csrf_token %}
<p>
<input id = "id" type = "file" class = "" name = "image">
</p>
<input type = "submit" value = "Submit" />
模型
class Display(models.Model):
title = models.CharField(max_length = 50,)
image = models.ImageField(upload_to = 'images')
id = models.UUIDField(primary_key = True, default = uuid.uuid4, unique = True)
def __str__(self):
return self.title
编辑:忘记发布表单代码抱歉
class ImageForm(forms.Form):
image = forms.ImageField()
进一步编辑:将我的表单类更改为此
class ImageForm(forms.Form):
class Meta:
model = Display
fields = ('image',)
允许表单由于某种原因被读取为有效,但我不明白为什么。不幸的是,这导致我的视图方法无法正常工作,因为它无法再读取
display.image = form.cleaned_data['image']
答案 0 :(得分:2)
如果你的表格是一个模型形式:class ImageForm(forms.ModelForm):
你可以将实例传递给表格并保存。
def display_update_image(request, pk):
if request.method == 'POST':
display = Display.objects.get(pk = pk)
form = ImageForm(request.POST, request.FILES, instance=display)
if form.is_valid():
form.save()
return HttpResponseRedirect(reverse('displays'))
else :
form = ImageForm()
return render(request, 'catalog/update_display_image.html', {'form': form})
答案 1 :(得分:0)
在forms.py
中检查您是否有像这样的Django表格:
class ImageForm(forms.ModelForm):
class Meta:
model = Display
fields = ['image',]
在template
添加{{ form }}
而非手动使用input
,如下所示:
<form method='post' enctype='multipart-formdata>
{% csrf_token %}
{{ form }}
<input type='submit' value='Update Image'>