Question

我正在努力开发我的第一款Android应用，但遇到了麻烦。我正在尝试构建和存档最简单的Android应用程序，并且无法使存档步骤起作用。

这是我正在做的......

使用Xamarin预览扩展和Xamarin更新程序（一切都已完全更新）启动VS2017预览

运行Android SDK Manager并安装以下

Android SDK Tools 25.2.5
Android SDK Platform-tools 26
Android SDK Build-tools 26
Android SDK Build-tools 25.0.3
Android SDK Build-tools 25.0.2
Android SDK Build-tools 25.0.1
Android SDK Build-tools 25
SDK Platform 25.3
Android Support Repository 47
Google Play Services 42
Instant Apps Development SDK 1
Google Play Licensing Library 1
Google Play Billing Library 5
Google USB Driver 11
Google Web Driver 2
Emulator 26

使用默认值创建新的跨平台（App1）（Xamarin.Forms - 空白应用程序 - 共享项目），我不对代码进行任何更改。

打开App1.Android Poperties

Compile using Android version: Android 7.1 (Nougat)
Package Name: App1
Version number: 1
Version name: 1.0
Minimum Android version: Android 7.1 (API Level 25 - Nougat)
Target Android version: Android 7.1 (API Level 25 - Nougat)
Linking: Sdk Assemblies Only
Everything else are default values

设置发布和构建：成功

存档：＆＃34; LinkAssemblies＆＃34;任务意外失败。

 Mono.Linker.MarkException: Error processing method: 'TNativeView Xamarin.Forms.Platform.Android.ViewRenderer'2::get_Control()' in assembly: 'Xamarin.Forms.Platform.Android.dll' ---> System.ArgumentNullException: Value cannot be null.
Parameter name: instruction
   at Mono.Cecil.Cil.InstructionOffset..ctor(Instruction instruction)
   at Mono.Cecil.Cil.CodeReader.ReadScope(ScopeDebugInformation scope)
   at Mono.Cecil.Cil.CodeReader.ReadScopes(Collection'1 scopes)
   at Mono.Cecil.Cil.CodeReader.ReadScope(ScopeDebugInformation scope)
   at Mono.Cecil.Cil.CodeReader.ReadScopes(Collection'1 scopes)
   at Mono.Cecil.Cil.CodeReader.ReadScope(ScopeDebugInformation scope)
   at Mono.Cecil.Cil.CodeReader.ReadDebugInfo()
   at Mono.Cecil.Cil.CodeReader.ReadMethodBody()
   at Mono.Cecil.Cil.CodeReader.ReadMethodBody(MethodDefinition method)
   at Mono.Cecil.MethodDefinition.<>c.<get_Body>b__41_0(MethodDefinition method, MetadataReader reader)
   at Mono.Cecil.ModuleDefinition.Read[TItem,TRet](TRet& variable, TItem item, Func'3 read)
   at Mono.Cecil.MethodDefinition.get_Body()
   at Mono.Linker.Steps.MarkStep.ProcessMethod(MethodDefinition method)
   at Mono.Linker.Steps.MarkStep.ProcessQueue()
   --- End of inner exception stack trace ---
   at Mono.Linker.Steps.MarkStep.ProcessQueue()
   at Mono.Linker.Steps.MarkStep.Process()
   at Mono.Linker.Steps.MarkStep.Process(LinkContext context)
   at Mono.Linker.Pipeline.Process(LinkContext context)
   at MonoDroid.Tuner.Linker.Process(LinkerOptions options, LinkContext& context)
   at Xamarin.Android.Tasks.LinkAssemblies.Execute(DirectoryAssemblyResolver res)
   at Xamarin.Android.Tasks.LinkAssemblies.Execute()
   at Microsoft.Build.BackEnd.TaskExecutionHost.Microsoft.Build.BackEnd.ITaskExecutionHost.Execute()
   at Microsoft.Build.BackEnd.TaskBuilder.<ExecuteInstantiatedTask>d__26.MoveNext()

我哪里错了？我怎么能弄乱这么简单的空白模板应用呢？

Answer 1

如果您转到Android项目的“属性”标签并选择“Android选项”，您会在“链接”标题下看到一个下拉列表，将其设置为“无”，然后重试。

如果此方法有效，请使用“仅限SDK Assemblies”再次尝试。通常，当发现无法原生链接的内容时，您会收到该错误。

非常简单的Xamarin.Forms应用程序赢得了归档

1 个答案: