我想为使用django-ckeditor / uploader上传的图片创建随机uid文件名。
我在与utils.py
相同的文件夹中创建了settings.py
:
import uuid
def get_name_uid():
ext = filename.split('.')[-1]
filename = "%s.%s" % (uuid.uuid4(), ext)
return filename
我想将此“随机”文件名添加到settings.py
:
CKEDITOR_FILENAME_GENERATOR = get_name_uid()
我该怎么做?我不知道如何获取在编辑器中上传的文件名。我应该将文件名从settings.py传递给utils.py吗?或者有不同的方法来做到这一点吗?
他们的文档说following:
``CKEDITOR_UPLOAD_PATH = "uploads/"``
When using default file system storage, images will be uploaded to "uploads" folder in your MEDIA_ROOT and urls will be created against MEDIA_URL (/media/uploads/image.jpg).
If you want be able for have control for filename generation, you have to add into settings yours custom filename generator.
```
# utils.py
def get_filename(filename):
return filename.upper()
```
```
# settings.py
CKEDITOR_FILENAME_GENERATOR = 'utils.get_filename'
```
CKEditor has been tested with django FileSystemStorage and S3BotoStorage.
There are issues using S3Storage from django-storages.
答案 0 :(得分:5)
这基本上都是在文档中为您详细说明的:
def get_filename(filename):
return filename.upper() # returns the uppercase version of filename
因此示例函数get_filename
获取传入的上传文件名,您应该返回您想要的文件名。这就是我们所说的callback。
回调作为参数传递的内容称为“回调签名”,文档整齐地指定了它的内容。
因此将函数放在makes sense的位置。我会选择mysite/mysite/utils.py
给定教程中概述的结构,标题为“让我们看一下创建的startproject:”。所以在与settings.py
相同的目录中。我将其命名为generate_uuid4_filename
,mysite/mysite/utils.py
将如下所示:
import uuid
import os.path
def generate_uuid4_filename(filename):
"""
Generates a uuid4 (random) filename, keeping file extension
:param filename: Filename passed in. In the general case, this will
be provided by django-ckeditor's uploader.
:return: Randomized filename in urn format.
:rtype: str
"""
discard, ext = os.path.splitext(filename)
basename = uuid.uuid4().urn
return ''.join(basename, ext)
现在更新您的settings.py
:
# Near the rest of the CKEditor variables
CKEDITOR_FILENAME_GENERATOR = '<app_label>.utils.generate_uuid4_filename'
你已经完成了。祝你好运!