Question

我希望这是一个相当简单的json问题。我有一个联系页面，我使用jquery函数将数据发送到c＃sendmail方法。这一切都有效。我发送信息回到jquery但有麻烦。

我的c＃是：

if (!ok) 
{
    return Json(new { success = false, responseText = "FAIL" }, 
     JsonRequestBehavior.AllowGet);
 }  
else
{
    return Json(new { success = true, responseText = "SENT" }, 
       JsonRequestBehavior.AllowGet);
}

和jquery的ajax部分是：

$.ajax({
    type: "POST",
    contentType: "application/json; charset=utf-8",
        processData: false,
        dataType: "json",
        cache:false,
        url: "x/sendEmail",
        dataType: 'json',
        data: JSON.stringify(myData),

        //complete changed to success
        success: function (response) {
            if (response != null && response.success) {
                alert(response.success + " pass" + response.responseText);
            } else {
                alert(response.success + " fail " + response.responseText);
            }
        },
        error: function (response) {
            alert(response.success + " fail2 " + response.responseText); 
        }

我将response.success视为true或false，但response.responseText始终是＆＃39; undefined＆＃39;。

不确定我缺少什么

我改变了C＃，但结果相同

public class ResponseObject
{
    public bool success { get; set; }
    public string responseText { get; set; }
}

public ActionResult sendEmail(string userName, string userEmail, string 
  userPhone, string userAddress,string userSubject, string userMessage, string 
  userList)
 {
       ///code to send mail - works no problem

       ResponseObject response;

        if (!ok)
        {
            //  Send "false"
            response = new ResponseObject { success = false, responseText = "FAIL" };
        }
        else
        {
            //  Send "Success"
            response = new ResponseObject { success = true, responseText = "Your message successfuly sent!" };
        }

        return Json(response, JsonRequestBehavior.AllowGet);
}

Answer 1

请尝试返回Content（您将需要Newtonsoft.Json包）

public ActionResult sendEmail(string userName, string userEmail,string userPhone, string userAddress, string userSubject, string userMessage, string userList)
{
       ///code to send mail - works no problem
        if (!ok)
        {
            //  Send "false"
            var response = new { success = false, responseText = "FAIL" };
            return Content(Newtonsoft.Json.JsonConvert.SerializeObject(response), "application/json");
        }
        else
        {
            //  Send "Success"
            var response = new { success = true, responseText = "Your message successfuly sent!" };
            return Content(Newtonsoft.Json.JsonConvert.SerializeObject(response), "application/json");
        }
}

Answer 2

按F12打开开发。工具，转到＆＃34;网络＆＃34;选项卡并再次进行AJAX调用。现在您应该能够找到调用sendEmail函数的URL。点击它，转到＆＃34;响应＆＃34;选项卡，查看服务器发送的响应。在那里，您将能够验证您是否同时接收所使用的属性和使用的格式（例如，可能是属性名称中的拼写错误）。

C＃返回json对象

2 个答案: