Question

你好我有一个表的想法，我想返回user_id =与经过身份验证的用户ID的行以及category_id =让我们假设为array [1,2,3]的行。免责声明：我希望退回这两个条件！

Answer 1

我知道你想要什么，但

有点问题

如果您想要经过身份验证的用户ID和类别ID的结果，您可以

$category_ids = [1, 2, 3];
$model->where('category_id', auth()->user->id)->whereIn('user_id', $ids)->get();

如果您想要经过身份验证的用户或category_ids在数组中的结果，您可以

$category_ids = [1,2,3];
$model->orWhere(function($q) use($category_ids) {
    $q->where('category_id', auth()->user->id);
    $q->whereIn('user_id', $category_ids);
})->get();

请注意，如果用户未被初始化，这将会中断，但我将其留给您做。

Answer 2

似乎是这样的：我认为您的表$categoryIds = [1, 2, 3]; $authUserId = Auth::user()->id; $ideas = Idea::where('user_id', $authUserId)->whereIn('category_id', $categoryIds)->get();和与此相关的模型Idea具有下一个结构： id，user_id，category_id和其他一些字段...

要获得Authenticated用户，您可以执行Auth :: user（）; 所以，你可以这样做：

with

如果您需要使用查询提取关系，可以添加$ideas = Idea::with('categories')->where('user_id', $authUserId)->whereIn('category_id', $categoryIds)->get();语句：

User.php

public function ideas() {
    return $this->hasMany('App\Idea');
}

somewhere in code:

$categoryIds = [1, 2, 3];
Auth()->user()->ideas()->whereIn('category_id', $categoryIds)->get();

ofc，您需要在模型中设置实际值

您还可以在用户模型中设置关系并获取与用户关联的记录：

$userIdeas = Idea::where('user_id', Auth::user()->id)->get();
$categoryIds = [1, 2, 3];
$categoryIdeas = Idea::where('user_id', '<>', Auth::user()->id)->whereId('category_id', $categoryIds)->get();
$mergedIdeas = $userIdeas->merge($categoryIdeas);

更新：要进行某种形式的加入，您可以使用：

$userId = Auth::user()->id;
$categoryIds = [1, 2, 3];
$ideas = Idea::where('user_id', $userId)->orWhere(function($query) use ($categoryIds) {
    $query->where('user_id', '<>', $userId)->whereIn('category_id', $categoryIds);
})->get();

最后。要在一个查询中执行此操作：

$firstArr=array("K"=>"location","L"=>"nearaddrss","M"=>"dsdsfll");
$secondArr=array(array("K"=>"loc","L"=>"Aggggkk","M"=>"dsdsfuu","A"=>"jhkhjg","B"=>"nnnn","C"=>"dsmmmmdsf"),array("K"=>"lo","L"=>"Aggggpp","M"=>"dsdsfjj","A"=>"jhkhjg","B"=>"nnnn","C"=>"dsmmmmdsf"));
$firstResultArr=array();
$secondResultArr=array();


$firstResultArr=array();
$secondResultArr=array();
foreach($secondArr as $key2 => $val2) {
foreach($val2 as $key3 => $val3) {
foreach ($firstArr as $key => $value) {
$firstResultArr[$value] = $val2[$key];

}
}
$secondResultArr[] =  $firstResultArr;
}

echo json_encode($secondResultArr);exit;

Laravel雄辩地回归两个条件

2 个答案: