在对象检测后更改矩形的大小

时间:2017-06-25 19:38:52

标签: c++ opencv rectangles

我使用下面的代码进行对象检测。

int main(int argc, char* argv[]){
VideoCapture cap(0); 
if (!cap.isOpened()){
    cout << "Cannot open the video cam" << endl;
    return -1;}
int totalFrameNumber = cap.get(CV_CAP_PROP_FRAME_COUNT);
Mat frame;
namedWindow("MyVideo", CV_WINDOW_AUTOSIZE);

while (1)
{
    bool bSuccess = cap.read(frame); // read a new frame from video

    if (!bSuccess)
    {
        cout << "Cannot read a frame from video stream" << endl;
        break;
    }
Mat frame2;

Rect rectangle2(420,280, 40, 40);
rectangle(frame, rectangle2, Scalar(255, 255, 255));
Mat cornerstrength;
    cornerHarris(frame, cornerstrength, 3, 3, 0.1);
    //threshold the corner strength
    Mat harriscorners;
    double th = 0.00001;
    threshold(cornerstrength, harriscorners, th, 255, THRESH_BINARY);
    morphologyEx(harriscorners, harriscorners, MORPH_CLOSE, Mat(), Point(-1, -1), 6);
    //local maxima detection
    Mat dilated, localMax;
    dilate(cornerstrength, dilated, Mat());
    compare(cornerstrength, dilated, localMax, CMP_EQ);
    threshold(cornerstrength, harriscorners, th, 255, THRESH_BINARY);
    harriscorners.convertTo(harriscorners, CV_8U);
    bitwise_and(harriscorners, localMax, harriscorners);
    harriscorners.convertTo(harriscorners, CV_32F);
    Mat S(0, 2, CV_32SC1);

    //drawing a circle around corners

    for (int j = 0;j < harriscorners.rows;j++)
        for (int i = 0;i < harriscorners.cols;i++)
        {

            if (harriscorners.at<float>(j, i)> 0)
            {    circle(frame, Point(i, j), 5, Scalar(255), 2, 8);
                Mat pt(1, 2, CV_32SC1);
                pt.at<int>(1, 0) = i;
                pt.at<int>(0, 1) = j;
                // Add the point to S
                S.push_back(pt);
                for (int x = 430; x < 460; x++)
                    for (int y = 285; y < 315; y++)
                        if  ((pt.at<int>(1, 0) = i) == x && (pt.at<int>(0, 1) = j) == y))


                        {
                            Rect rectangle2(430, 285, 30,30);}}}
imshow("MyVideo", frame);
if (waitKey(30) == 27)
                {
                    cout << "esc key is pressed by user" << endl;
                    break;
                }
            }

            return 0;
        }

我想当条件 if((pt.at(1,0)= i)== x&amp;&amp;(pt.at(0,1)= j)== y))< / strong>然后建立矩形2的大小 rectangle2(420,280,40,40)更改为 rectangle2(430,285,30,30)。我可以执行此更改但是当我使用我的代码时两个矩形(前一个矩形2和new rectangle2)显示在picture.but我想显示onle new rectangle2.do你有任何想法解决我的问题?非常感谢..

1 个答案:

答案 0 :(得分:0)

正如我在评论中所说,你需要创建一个克隆并保持框架几乎不变。

所以,在这一部分:

    Rect rectangle2(420,280, 40, 40);
    rectangle(frame, rectangle2, Scalar(255, 255, 255));
    Mat cornerstrength;
    cornerHarris(frame, cornerstrength, 3, 3, 0.1);

写一些更像这样的东西

    cv::Mat frameCopy = frame.clone();
    Rect rectangle2(420,280, 40, 40);
    rectangle(frameCopy , rectangle2, Scalar(255, 255, 255));
    Mat cornerstrength;
    cornerHarris(frameCopy , cornerstrength, 3, 3, 0.1);

然后,在这部分中,我不确定它的目的是什么

                for (int x = 430; x < 460; x++)
                    for (int y = 285; y < 315; y++)
                        if  ((pt.at<int>(1, 0) = i) == x && (pt.at<int>(0, 1) = j) == y))    
                        {
                            Rect rectangle2(430, 285, 30,30);
                        }
             }
         }
                            imshow("MyVideo", frame);

但是你可能想用新的矩形显示新图像,所以你可以再做一次像以前那样:

    cv::Mat anotherCopy= frame.clone();
    Rect rectangleInLoop(430,280,30,30);
    rectangle(anotherCopy, rectangleInLoop, Scalar(255, 255, 255));
    imshow("MyVideo", anotherCopy);