使用COUNT（id）作为条件的条件SELECT COUNT（id）？

Question

我想只选择分配给该类别的文章数量超过3的类别ID。

我尝试了各种排列并发布了下面的一个，我觉得最清楚地解释了我正在尝试做的事情，尽管我有一种感觉我需要使用嵌套的SELECT。我尝试过嵌套的SELECT，但没有成功。

SELECT categoryID, COUNT(articleID) AS numArticles 
FROM articles GROUP BY categoryID WHERE numArticles > 3

Answer 1

使用having

SELECT categoryID, COUNT(articleID) AS numArticles 
FROM articles GROUP BY categoryID HAVING COUNT(articleID) > 3

Answer 2

SELECT categoryID, COUNT(articleID) AS numArticles 
FROM articles GROUP BY categoryID 
HAVING COUNT(articleID) > 3

Answer 3

您需要使用Having子句

Select CategoryId, Count(ArticleId) as numArticles
From dbo.Articles
Group By CategoryId
Having Count(ArticleId) > 3

Answer 4

使用HAVING条款：

SELECT categoryID, COUNT(articleID) AS numArticles 
FROM articles 
 GROUP BY categoryID 
 HAVING COUNT(articleID) > 3

来自MSDN：

  

指定组或聚合的搜索条件。 HAVING只能与SELECT语句一起使用。 HAVING通常用于GROUP BY子句。不使用GROUP BY时，HAVING的行为类似于WHERE子句。

Answer 5

改为使用HAVING。

http://techonthenet.com/sql/having.php

Answer 6

为此不要使用WHERE，你必须使用HAVING。

试试这个：

SELECT categoryID, COUNT(articleID) AS numArticles 
FROM articles GROUP BY categoryID HAVING numArticles > 3